Mia and John are selling boxes of apples. They have small boxes and large boxes. Mia sells 6 small boxes and 2 large boxes for a
total of $28. John sells 4 small boxes and 5 large boxes for a total of $37. How much does each small box and each large box cost?
2 answers:
so
6s+2l = 28
4s+5l= 37
eliminate 6s+2l=28 by dividing all numbers by 6
u get s= -1/3 l + 14/3
49-1/3l=14/3) + 5l =37
L=5
s= -1/3(5) + 14/3
s=3
l=5
Answer:
Smalls boxes: $3
Large boxes: $5
Step-by-step explanation:
Small boxes: x
Large boxes: y
6x + 2y = 28
4x + 5y = 37
I will use elimination to solve it.
2(6x + 2y = 28) = 12x + 4y = 56
-3 (4x + 5y = 37) = -12x + 15y = -111
(4y = 56) + (-15y = -111)
4y -15y = -11y and 56 - 111 = -55
-11y = -55
y = 5
6x + 2(5) =28
6x = 28-10
x = 18/6
x = 3
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