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Wewaii [24]
3 years ago
15

Calculate each value for ⊙P. Use 3.14 for π and round to the nearest tenth.

Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

Area of the unshaded sector = 113.4 sq units

Area of the shaded sector = 200.6 sq units

Step-by-step explanation:

First let us calculate the area of the circle

Area of the circle = πr²

radius r  = 10units

Area of the circle = π(10)²

Area of the circle = π(100)

Area of the circle = 3.14(100)

Area of the circle = 314 sq. units

Area of a sector = theta/360 * πr²

Area of the unshaded sector = 130/360 * 314

Area of the unshaded sector = 13/36 * 314

Area of the unshaded sector = 113.389 sq units

Area of the unshaded sector = 113.4 sq units

Area of the shaded sector = Area of circle - Area of the unshaded sector

Area of the shaded sector = 314 - 113.89

Area of the shaded sector = 200.6sq. units

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If 60 of the 200 students are girls, then what percent of the students are girls?
OlgaM077 [116]
30%?
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5 0
3 years ago
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Pls help me and give steps as to how to do it thank you
andrew11 [14]

Answer: x=13, y=132

Step-by-step explanation:

Using the same-side interior angles theorem, y=132.

Using the alternate interior angles theorem, 5x-17=48 \implies x=13

7 0
1 year ago
Please help ASAP <br> Questions 1 and 2 plzzzzz
liubo4ka [24]

Take the sequence in 1a

The 10th term is 31

The 20th is 61

If you wanted to find these by continuing the series, you'd have to add 3 to the last number in the series, then 3 more, then 3 more, until you reach the 20th term. By this point, you will have added 3 to the first term 19 times. That's where the formula comes from. So here,

a = 4, the first term

n = 20, the number of the term we need

d = 3, how much we're adding each time between one term and the next

Then, to get the 20th term,

4 + (20 - 1) • 3 = 4 + (19 • 3) = 4 + 57 = 61

Answers

The 10th and 20th terms of each sequences are

a. 31; 61

b. 48; 98

c. 47; 97

(in <em>c</em>, you're adding the same <em>d</em> as in the sequence above, but your first term is one unit less)

d. -25; -75

(same thing as before, but now, <em>d</em> is negative)

e. 11.5; 16.5

(with <em>d</em>=1/2 or 0.5)

f. 6+1/2; 8+1/2

Use these to check your answers after applying the formula, but know that I calculated on the fly and didn't check these.

5 0
3 years ago
Find the range of the function y=-x^2-3x when the domain is {-5, 0, 2}
ankoles [38]

The range of the function y = -x² - 3x when the domain is {-5,0,2} is:

{-10, 0}.

<h3>What is the range of a function?</h3>

The range of a function is the set that contains the output values for the given domain of the function.

In this problem, the domain is:

{-5,0,2}.

Hence the output values are:

  • -(-5)² - 3(-5) = -25 + 15 = -10.
  • -(0)² - 3(0) = 0.
  • -(2)² - 3(2) = -4 + -6 = -10.

Hence the range is:

{-10, 0}.

-10 repeats, but goes only once on the range.

More can be learned about the range of a function at brainly.com/question/10891721

#SPJ1

7 0
2 years ago
Write five ordered pairs in a table to represent a relation that is not a function.
QveST [7]

Answer:

Therefore, the relation of the given ordered pairs does NOT represent a function as that x-coordinate values are repeated.

Step-by-step explanation:

We know that a relation is basically a set of input and output values, which are expressed in ordered pairs.

A relation may have any set of ordered pairs.

We also know that a function is a set of ordered pairs in which each x-element has only one y-element associated with it.

Consider the five ordered pairs

x                       y

-2                      1

3                       -4

-2                      -7

4                        6

5                         7

The relation is: {(–2, 1), (3, –4), (–2, –6), (4, 6), (5, 7)}

From the table, it is clear that x-coordinate values are repeated.

In other words, x = -2 twice.

Therefore, the relation of the given ordered pairs does NOT represent a function.

8 0
3 years ago
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