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The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time.
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Answer:
The work done to get you safely away from the test is 2.47 X 10⁴ J.
Explanation:
Given;
length of the rope, L = 70 ft
mass per unit length of the rope, μ = 2 lb/ft
your mass, W = 120 lbs
mass of the 70 ft rope = 2 lb/ft x 70 ft
= 140 lbs.
Total mass to be pulled to the helicopter, M = 120 lbs + 140 lbs
= 260 lbs
The work done is calculated from work-energy theorem as follows;
W = Mgh
where;
g is acceleration due gravity = 32.17 ft/s²
h is height the total mass is raised = length of the rope = 70 ft
W = 260 Lb x 32.17 ft/s² x 70 ft
W = 585494 lb.ft²/s²
1 lb.ft²/s² = 0.0421 J
W = 585494 lb.ft²/s² = 2.47 X 10⁴ J.
Therefore, the work done to get you safely away from the test is 2.47 X 10⁴ J.
Answer:

Explanation:
Initial speed of the electron, u = 0
The charge per unit area of each plate, 
Separation between the plates, 
An electron is released from rest, u = 0
Using equation of kinematics,
..........(1)
Acceleration of the electron in electric field,
............(2)
Electric field,
............(3)
From equation (1), (2) and (3) :


v = 10840393.1799 m/s
or

So, the electron is moving with a speed of
before it reaches the positive plate. Hence, this is the required solution.
A) 8.11 m/s
For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

where
m is the satellite's mass
v is the speed
R is the radius of the asteroide
h is the altitude of the satellite
G is the gravitational constant
M is the mass of the asteroid
Solving the equation for v, we find

where:




Substituting into the formula,

B) 11.47 m/s
The escape speed of an object from the surface of a planet/asteroid is given by

where:




Substituting into the formula, we find:
