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Wewaii [24]
4 years ago
15

At a waterpark, sleds with riders are sent along a slippery, horizontal surface by the release of a large, compressed spring. Th

e spring with a force constant 37.0 N/cm and negligible mass rests on the frictionless horizontal surface. One end is in contact with a stationary wall. A sled and rider with total mass 66.0 kg are pushed against the other end, compressing the spring 0.370 m. The sled is then released with zero initial velocity.
What is the sled's speed when the spring is still compressed 0.180 m?

Physics
2 answers:
jekas [21]4 years ago
8 0

Answer:

2.2 m/s

Explanation:

<u>solution:</u>

To calculate change in stored energy at desired extension

ΔU = 1/2*k*(δx)^2

     = 1/2*3700*(0.37^2-0.180^2)

     = 201 N.m

use work energy theorem

ΔU = ΔK = 1/2*m*v^2 = 201

              = 2.2 m/s

<u>note:</u>

calculation maybe wrong but method is correct.

sweet [91]4 years ago
5 0

Explanation:

Below is an attachment containing the solution.

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1. Which of the following is the BEST synonym for synthetic?
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Answer:

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3 years ago
A soil sample contains 55 percent sand, 25 percent clay, and 20 percent silt. What type of soil is present in the sample?
Step2247 [10]

Answer: D (sandy clay loam)

Explanation:

It is because it is 55 percent sand, and 25 percent clay, so it has to be more sandy than silty. Much of it is by sand, so it is sandy. Loam is a fertile soil of clay and sand, so it is D.

7 0
3 years ago
After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average
alexira [117]

Answer:

Incomplete Question

Explanation:

String constant is not stated

I'll solve this in a general way.

At the end of my explanation, I'll assume any value for string constant.

The total weight on the taptap : Weight of people + Weight of goats + Weight of chickens + weight of banana

= (25 * 66) + (3 * 15) + (5 * 3) + 25 = 1735 kg

The gravitational force exerted on the taptap

Fig = m*g

where m = the total mass 1735kg

and g = 9.8m/s²

Hooke's law of Elasticity states that

Fs = Kx

Where Fs = spring force

k = spring constant

x = spring stretch or compression

Since Fs = Fg

So, Kx = mg

Make x the subject of the formula

x = mg/k --------------- This is the general way of solving for spring compressor in cases like this

I'll replace m and g with their values, respectively.

Because, the spring constant (k) is omitted in the question, I'll assume it to be 30000

x = 1735 * 9.8/30000

x = 17003/30000

x = 0.566767 metres

x = 0.57 metres ------------- Approximated

In conclusion, the spring compression is 0.57 metres if the spring constant is 30000

6 0
3 years ago
an oscilloscope has a time/div setting of 50ms and there are 10 divisions on the time scale. a sine wave on the oscilloscope dis
mamaluj [8]

Answer:

The frequency is f = 6Hz

Explanation:

Given

         The time division  setting is  d_t =50ms = 50*10^{-3}s

         The number of division is  n= 10

The total time for 10 division can be mathematically obtained as

         T_{total} = 10 *50*10^{-3}

                 =500 *10^{-3}s

From the question the time for 3 cycle is

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Then the for one cycle which equivalent to the Period(T)  =  \frac{T_{total}}{3}

                                                               = \frac{500 *10^{-3}}{3}

The frequency is generally given as    f = \frac{1}{period} = \frac{1}{T}

    Now substituting values we have  

                              f = \frac{3}{500 *10^{-3}}

                                 = 6Hz

                 

4 0
4 years ago
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