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navik [9.2K]
2 years ago
11

What line is parallel to 2x+5y=6 that goes through (5,3)

Mathematics
1 answer:
Anna11 [10]2 years ago
7 0

Answer:

4y = x - 17

Step-by-step explanation:

First off, in the equation given : 2x + 5y = 6 , make y the subject of the formula which will give y = \frac{-2x}{5} + \frac{6}{5}  which make the gradient, m, the coefficient of x = \frac{-2}{5}  . Since the line we're looking for is parallel to the one we were given, their respective gradients would be the same. (If they were perpendicular, the gradient of the new line would be a negative inverse of the given line)

Then you proceed to use the one-point formula : y - y₀ = m(x - x₀), where   y₀ = 3 and x₀ = 5 from the point it goes through (5, 3)

y - 3 = \frac{1}{4}(x - 5); y - 3 = \frac{x}{4} - \frac{5}{4};  y = \frac{x}{4} - \frac{5}{4} +3

y = \frac{x}{4} - \frac{17}{4};  y = \frac{x-17}{4}  ;   4y = x - 17

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Find the rectangular coordinates of the point with the polar coordinates (3, 3 divided by 2 pi ). (1 point)
kifflom [539]

Answer:

The correct choice is (0,-3)

Step-by-step explanation:

To convert from polar coordinates to rectangular coordinates, we use the parametric equations:

x=r\cos \theta and y=r\sin \theta

The point given to us in polar coordinates is (3,\frac{3}{2}\pi).

where r=3,\theta=\frac{3\pi}{2}

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Anettt [7]

Answer:

Choice C: approximately 121 green beans will be 13 centimeters or shorter.

Step-by-step explanation:

What's the probability that a green bean from this sale is shorter than 13 centimeters?

Let the length of a green bean be X centimeters.

X follows a normal distribution with

  • mean \mu = 11.2 and
  • standard deviation \sigma = 2.1.

In other words,

X\sim \text{N}(11.2, 2.1^{2}),

and the probability in question is X \le 13.

Z-score table approach:

Find the z-score of this measurement:

\displaystyle z= \frac{x-\mu}{\sigma} = \frac{13-11.2}{2.1} = 0.857143. Closest to 0.86.

Look up the z-score in a table. Keep in mind that entries on a typical z-score table gives the probability of the left tail, which is the chance that Z will be less than or equal to the z-score in question. (In case the question is asking for the probability that Z is greater than the z-score, subtract the value from table from 1.)

P(X\le 13) = P(Z \le 0.857143) \approx 0.8051.

"Technology" Approach

Depending on the manufacturer, the steps generally include:

  • Locate the cumulative probability function (cdf) for normal distributions.
  • Enter the lower and upper bound. The lower bound shall be a very negative number such as -10^{9}. For the upper bound, enter 13
  • Enter the mean and standard deviation (or variance if required).
  • Evaluate.

For example, on a Texas Instruments TI-84, evaluating \text{normalcdf})(-1\text{E}99,\;13,\;11.2,\;2.1 ) gives 0.804317.

As a result,

P(X\le 13) = 0.804317.

Number of green beans that are shorter than 13 centimeters:

Assume that the length of green beans for sale are independent of each other. The probability that each green bean is shorter than 13 centimeters is constant. As a result, the number of green beans out of 150 that are shorter than 13 centimeters follow a binomial distribution.

  • Number of trials n: 150.
  • Probability of success p: 0.804317.

Let Y be the number of green beans out of this 150 that are shorter than 13 centimeters. Y\sim\text{B}(150,0.804317).

The expected value of a binomial random variable is the product of the number of trials and the probability of success on each trial. In other words,

E(Y) = n\cdot p = 150 \times 0.804317 = 120.648\approx 121

The expected number of green beans out of this 150 that are shorter than 13 centimeters will thus be approximately 121.

7 0
3 years ago
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