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1 year ago

4<4x+8<20 HELPPP ME PLS

Mathematics

1 answer:

ratelena [41]1 year ago

4 0

Step-by-step explanation:

let's break it down first

$4x + 8 < 20$

$4x < 20 - 8$

$4x < 12$

Divide both sides by the coefficient of x which is 4

$4x \div 4 < 12 \div 4$

$x < 3$

$4 < x < 3$

4 is less than x which is greater than 3

x = 4,5,6,7,8,......

since 4 is less than x, x cannot be 4

so x could be 5,6,7,8,9,.......

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The function f(x) = 5One-fifth is reflected over the y-axis. Which equations represent the reflected function? Select two option

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Answer:

The equations that represent the reflected function are

$f(x)=5(\frac{1}{5})^{-x}$

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Step-by-step explanation:

The correct question in the attached figure

we have the function

$f(x)=5(\frac{1}{5})^{x}$

we know that

A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.

therefore

$f(−x) = f(x).$

The reflection of the given function across the y-axis will be equal to

(Remember interchanges positive x-values with negative x-values)

$f(x)=5(\frac{1}{5})^{-x}$

An equivalent form will be

$f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}$

therefore

The equations that represent the reflected function are

$f(x)=5(\frac{1}{5})^{-x}$

$f(x)=5(5)^{x}$

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4<4x+8<20￼￼ HELPPP ME PLS

4<4x+8<20 HELPPP ME PLS