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3 years ago

If the Humidity of grass is 85% and the humidity of Hay is 10%. How many Tonnes of Hay can we get From 15Tonnes of Grass.

Mathematics

2 answers:

Sveta_85 [38]3 years ago

5 0

We have to find 10% of 15tonnes

$\\ \bull\tt\looparrowright 10\%\:of\:15$

$\\ \bull\tt\looparrowright \dfrac{10}{100}\times 15$

$\\ \bull\tt\looparrowright \dfrac{150}{100}$

$\\ \bull\tt\looparrowright 1.5\;tonnes$

Liono4ka [1.6K]3 years ago

4 0

$10 \: per \: cent \: of \: 15. \\ \frac{10}{100} \times 15 \\ \frac{150}{100} \\ = 1.5tonnes.$

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The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events. (a) The cou

Scilla [17]

Answer:

a) correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is 0.0536

Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as $\sigma^2 = mean = 6.2$

hence, standard deviation is given as $\sqrt{6.2} = 2.48998$

thus standard deviation is 2.49

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is

$P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)$

$= \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}$

= 0.002029 + 0.012582+ 0.039006

= 0.053617

= 0.0536

7 0

3 years ago

Identify the usual level of measurement for each of the following A. year in school B. IQ scores C. life expectancy D. fatigue E

Mashutka [201]

Answer:

The answer is C

Step-by-step explanation:

4 0

3 years ago

Please help me ASAP

stellarik [79]

Answer:

<em>The Graph is shown below</em>

Step-by-step explanation:

<u>The Graph of a Function</u>

Given the function:

$\displaystyle y=g(x)=-\frac{3}{2}(x-2)^2$

It's required to plot the graph of g(x). Let's give x some values:

x={-2,0,2,4,6}

And calculate the values of y:

$\displaystyle y=g(-2)=-\frac{3}{2}(-2-2)^2=-\frac{3}{2}(-4)^2==-\frac{3}{2}*16=-24$

Point (-2,-24)

$\displaystyle y=g(0)=-\frac{3}{2}(0-2)^2=-\frac{3}{2}(-2)^2=-\frac{3}{2}*4=-6$

Point (0,-6)

$\displaystyle y=g(2)=-\frac{3}{2}(2-2)^2=-\frac{3}{2}(0)^2=0$

Point (2,0)

$\displaystyle y=g(4)=-\frac{3}{2}(4-2)^2=-\frac{3}{2}(2)^2=-\frac{3}{2}*4=-6$

Point (4,-6)

$\displaystyle y=g(6)=-\frac{3}{2}(6-2)^2=-\frac{3}{2}(4)^2=-\frac{3}{2}*16=-24$

Point (6,-24)

The graph is shown in the image below

8 0

3 years ago

In ∆PQR, ∠P = 90degrees , PQ= 12 cm, PR=16cm. Find ∠Q

siniylev [52]

Answer:

∠Q = 53.13 degrees

Step-by-step explanation:

Given that ∆PQR, ∠P = 90degrees , this means that the triangle is a right angled triangle

Hence using the notation

SOH CAH TOA

where S is sine, C is cosine, T is tangent and O, A and H represents the size of the opposite, adjacent and hypotenuse sides

Considering ∠Q and the given sides

PR=16cm is the opposite side,

PQ= 12 cm is the adjacent side hence we use TOA

Tan Q = 16/12 =

Q = Arc tan 16/12

= 53.13 degrees

5 0

3 years ago

What is the slope of the line passing through the points (1, –5) and (4, 1)?

xxMikexx [17]

You are given two points that could be plotted on a graph (1,-5) and (4,1). The formula for slope is y2-y1/x2 -x1

When plotted into the points it would look like 1-(-5)/4-1= 6/3

6/3=2. So, the slope for these two points is 2.

8 0

3 years ago