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jek_recluse [69]

2 years ago

7

A bag contains 6 blue marbles and 30 white mark marbles if a representative sample contains 3 blue marbles then how many white m

arbles would you expect to contain

2 answers:

jasenka [17]2 years ago

4 0

Answer:

10

Step-by-step explanation:

vovikov84 [41]2 years ago

3 0

I would expect it to contain 10

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Convert 81° to radians.

SOVA2 [1]

Answer: 9π/20 radians

How to: <u>Convert from degrees to radians using the ratio π/180 .</u>

Have a great day !

7 0

2 years ago

Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)).

Alex

We are given with two functions: f(x) = x + 8 and g(x) = x2 - 6x - 7. In this problem, the value of f(g(2)) is asked. We first substitute g(x) to f(x) resulting to f(x2 - 6x - 7) = x2 - 6x - 7 + 8 = x2 - 6x + 1. If x is equal to 2, then <span>f(g(2)) = 2^</span>2 - 6*2 + 1 equal to -7.

6 0

2 years ago

I need help finding the answers to these questions thank you soo much!!!!

anzhelika [568]

Hopefully this helps you ..

3 0

2 years ago

Need Help!!! ASAP

RoseWind [281]

Answer:

$P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}$

$P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}$

$P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}$

Step-by-step explanation:

The given probabilities are:

$P(red)=\frac{2}{7}$

$P(blue)=\frac{3}{14}$

Their sum is $P(red)+P(blue)=\frac{2}{7}+\frac{3}{14}$

The probabilities that will complete the model should add up to $\frac{1}{2}$ so that the sum of all probabilities is 1.

$P(green)+P(yellow)=\frac{2}{7}+\frac{2}{7}\ne\frac{1}{2}$

$P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}=\frac{1}{2}$

$P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}$

$P(green)+P(yellow)=\frac{5}{21}+\frac{11}{21}\ne\frac{1}{2}$

$P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}=\frac{1}{2}$

5 0

3 years ago

Trey is putting up a fence around a 750 foot by 540 foot lot. How many feet of fence dose he need?

anygoal [31]

Given:

The length of the lot l= 750ft

The width of the plot w= 540 ft

Required:

Find the required fence.

Explanation:

The perimeter of the rectangle is given by the formula.

$P=2(length+width)$

Thus the required fence for the lot

$\begin{gathered} =2(750+540) \\ =2(1290) \\ =2580\text{ ft} \end{gathered}$

Final answer:

The required fence is 2580 ft.

6 0

4 months ago