Question

A grapefruit falls from a tree and hits the ground 0.80 s later.

Answer 1

This question can be solved by using equations of motion.

A. The grapefruit dropped by "3.1 m".

B. The speed of the grapefruit, when it hit the ground was "7.8 m/s".

A.

We will use the second equation of motion here to find out the distance dropped by the grapefruit:

$h = v_it+\frac{1}{2}gt^2$

where,

h = height dropped = ?

vi = initial speed = 0 m/s

t = time period = 0.8 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$h = (0\ m/s)(0.8\ s)+\frac{1}{2}(9.81\ m/s^2)(0.8\ s)^2$

h = 3.1 m

B.

Now, we will use the first equation of motion to find out the final speed:

$v_f = v_i +gt$

vf = 0 m/s + (9.81 m/s²)(0.8 s)

vf = 7.8 m/s

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.