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dsp73
3 years ago
5

A grapefruit falls from a tree and hits the ground 0.80 s later.

Physics
1 answer:
Sonbull [250]3 years ago
8 0

This question can be solved by using equations of motion.

A. The grapefruit dropped by "3.1 m".

B. The speed of the grapefruit, when it hit the ground was "7.8 m/s".

A.

We will use the second <em>equation of motion</em> here to find out the distance dropped by the grapefruit:

h = v_it+\frac{1}{2}gt^2

where,

h = height dropped = ?

vi = initial speed = 0 m/s

t = time period = 0.8 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

h = (0\ m/s)(0.8\ s)+\frac{1}{2}(9.81\ m/s^2)(0.8\ s)^2

<u>h = 3.1 m</u>

<u />

B.

Now, we will use the first <em>equation of motion </em>to find out the final speed:

v_f = v_i +gt

vf = 0 m/s + (9.81 m/s²)(0.8 s)

<u>vf = 7.8 m/s</u>

<u />

Learn more about <em>equations of motion</em> here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

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