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3 years ago

How far would the moon be if its mass was doubled

Physics

2 answers:

Serhud [2]3 years ago

4 0

Explanation:

If the moon doubled in mass, that means that the Earth will not experience a total solar eclipse like today. Also, if it doubled in mass, tide waves would increase in size, as the moon would be bigger and would have a bigger gravitational pull. Also, gravity would be different on earth because the moon is bigger (gravity law by mass). Also, the sky would be ‘smaller’ than our actual sky

Alex73 [517]3 years ago

4 0

Answer:

If the moon's mass doubles, the Earth will not witness a total solar eclipse as today. Also, if its mass doubled, tide waves would double in size since the moon would be bigger and have a stronger gravitational attraction. Also, because the moon is larger, gravity on Earth would be different (gravity law by mass). Also, the sky would be "smaller" than it is now.

Hope I helped! ☺

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How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00

klio [65]

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is $9 \times 10^{-4} m^{2}$ . As the capacitance of capacitor is given as follows.

C = $\frac{\epsilon_{o}A}{d}$

It is known that the dielectric strength of air is as follows.

E = $3 \times 10^{6} V/m$

Expression for maximum potential difference is that the capacitor can with stand is as follows.

dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

Q = CV

= $\frac{\epsilon_{o} A}{d} \times E \times d$

= $\epsilon_{o}AE$

= $8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}$

= $1.062 \times 10^{-8} C$

or, = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

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4 years ago

A 230.-mL sample of a 0.240 M solution is left on a hot plate overnight; the following morning, the solution is 1.75 M. What vol

Gwar [14]

Answer:

The volume of water evaporated is 199mL

Explanation:

Concentration is calculated with the following formula

$C=\frac{n}{V}$

where n is the number of moles of solute and V is the volume of the solution (in this case is the same as the solvent volume) in liters.

So we isolate the variable n to know the amount of moles, using the volume given in liters

$230mL=0.23L$

$n=C*V=0.240 M*0.23L=0.055 mol$

Now, we isolate the variable V to know the new volume with the new concentration given.

$V=\frac{n}{C} =0.055mol/1.75M=0.031L=31mL$

Finally, the volume of water evaporated is the difference between initial and final volume.

$V_{ev}= V_{i} -V_{f} =230mL-31mL=199mL$

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3 years ago

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pychu [463]

2 is the answer have a nice day <3

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3 years ago

Rest and motion are inter-related to each other, explain

mamaluj [8]

Answer:

Rest and motion are the relative terms because they depend on the observer's frame of reference. So if two different observers are not at rest with respect to each other, then they too get different results when they observe the motion or rest of a body.

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4 years ago

Read 2 more answers

As shown in the figure above, a 50 kg box is dragged across the floor with a pulling force (Fp) of 200 N which acts at an angle

Nat2105 [25]

Answer:

The acceleration of the box is 2.05 m/s²

Explanation:

The given parameters of the motion of the box are;

The mass of the box, m = 50 kg

The pulling force, $F_p$ acting on the box = 200 N