Answer:
They would keep on moving but unless being acted upon or stop slowly because of the friction
Explanation:
So,
GPE (graviational potential energy) = mass x g x height
GPE is depends on where zero height is defined. In this situation, we define h = 0 as the initial height.
![GPE = 75 \ kg*9.8 \ \frac{m}{s^2}*25 \ m](https://tex.z-dn.net/?f=GPE%20%3D%2075%20%5C%20kg%2A9.8%20%5C%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%2A25%20%5C%20m)
![GPE = 18,375 \frac{kg*m^2}{s^2}](https://tex.z-dn.net/?f=GPE%20%3D%2018%2C375%20%5Cfrac%7Bkg%2Am%5E2%7D%7Bs%5E2%7D)
![GPE = 18,375 \ joules(J) \ or \ 18.375 \ kilojoules(kJ)](https://tex.z-dn.net/?f=GPE%20%3D%2018%2C375%20%5C%20joules%28J%29%20%5C%20or%20%5C%2018.375%20%5C%20kilojoules%28kJ%29)
The builder has gained 18.375 kJ of PE.
Answer:
Q = 282,000 J
Explanation:
Given that,
The mass of liquid water, m = 125 g
Temperature, T = 100°C
The latent heat of vaporization, Hv = 2258 J/g.
We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :
![Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J](https://tex.z-dn.net/?f=Q%3DmH_v%5C%5C%5C%5CQ%3D125%5C%20g%5Ctimes%202285%5C%20J%2Fg%5C%5C%5C%5CQ%3D282250%5C%20J)
or
Q = 282,000 J
So, the required heat is 282,000 J
.
This is possible due to self-discharge. Very small internal currents inevitably occur in these cells over time and they will eventually exhaust the chemistry.
Answer:
<h3>2,321.62Joules</h3>
Explanation:
The formula for calculating workdone is expressed as;
Workdone = Force * Distance
Get the force
F = nR
n is the coefficient of friction = 0.5
R is the reaction = mg
R = 46 ( 9.8)
R = 450.8N
F = 0.5 * 450.8
F = 225.4N
Distance = 10.3m
Get the workdone
Workdone = 225.4 * 10.3
Workdone = 2,321.62Joules
<em>Hence the amount of work done is 2,321.62Joules</em>