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Liono4ka [1.6K]
3 years ago
8

F(x) = x/ (x^2 + 4x - 21) how do i find the domain and range?

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

Step-by-step explanation:

F(x) = x/ (x^2 + 4x - 21)

F(x)= x / (x - 3)(x + 7)

When x = 3 and x = -7 the denominator is zero  so there are no values of the function corresponding to these values of x.

The domain is all Real x except x = -7 and x = 3.

The range is all values of f(x) except for those values when x = -7 and x = 3.

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Step-by-step explanation:

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I NEED HELP PLEASE, THANKS! :)
saw5 [17]

Hey there! :)

Answer:

First option: As x⇒ ∞ f(x) ⇒ -∞.  As x⇒ -∞ f(x) ⇒ ∞.

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4 0
3 years ago
Find d<br><br> a * a * a = 216<br> a * b * c = 96<br> b * c = 52<br> a + b + c = d
Slav-nsk [51]

a\cdot a\cdot a=216\\\\a^3=216\to a=\sqrt[3]{216}\\\\\boxed{a=6}\\\\\text{Substitute}\ b\cdot c=52\ \text{to the second expression}\ a\cdot b\cdot c=96:\\\\abc96\ \wedge\ bc=52\to a(52)=96\qquad\text{divide both sides by 52}\\\\a=\dfrac{96}{52}\to a=\dfrac{24}{13}\neq6

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<h3>Answer: NO SOLUTION.</h3>
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3 years ago
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Answer:

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Hope this helps!

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3 years ago
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