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Liono4ka [1.6K]
3 years ago
8

F(x) = x/ (x^2 + 4x - 21) how do i find the domain and range?

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

Step-by-step explanation:

F(x) = x/ (x^2 + 4x - 21)

F(x)= x / (x - 3)(x + 7)

When x = 3 and x = -7 the denominator is zero  so there are no values of the function corresponding to these values of x.

The domain is all Real x except x = -7 and x = 3.

The range is all values of f(x) except for those values when x = -7 and x = 3.

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The vertex of this parabola is at (-4,-1).When the y-value is 0,the x-value is 2.What is the coefficient of the squared term in
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Answer:

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Step-by-step explanation:

When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.

The coefficient of the squared term is 1/36.

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3 years ago
E + f =48<br> e=3f<br> Plz help - thanks
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Answer:

given \:  \\ \\ e = 3f \\  e + f = 48 \\  \\ 3f + f = 48 \\   4f = 48 \\ f =  \frac{48}{4}  \\ f = 12 \\ so. \\ e = 3 \times 12 = 36

<h2><em>plzz mark it as a brilliant ans</em></h2>
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Agent Bond is standing on a bridge, 13.5 m above the road below, and his pursuers are getting too close for comfort. He spots a
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Step-by-step explanation:

Eek!  Let's give this a go. Things we know:

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Good luck with this!

Cheers!

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