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Liono4ka [1.6K]
3 years ago
8

F(x) = x/ (x^2 + 4x - 21) how do i find the domain and range?

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

Step-by-step explanation:

F(x) = x/ (x^2 + 4x - 21)

F(x)= x / (x - 3)(x + 7)

When x = 3 and x = -7 the denominator is zero  so there are no values of the function corresponding to these values of x.

The domain is all Real x except x = -7 and x = 3.

The range is all values of f(x) except for those values when x = -7 and x = 3.

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Oksanka [162]

Answer:

Blonde: 54 for mountains

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Total: 162 for beach, 197 for mountains, 360 for total

Step-by-step explanation:

add and subtract as needed

6 0
3 years ago
If g(x)=2x+3 is a function,then find the unknown term in the following ordered pairs.
Dmitrij [34]

Answer:

a=2, b = 1, m=9

Step-by-step explanation:

i. 7 = 2a+3 -----> 4=2a---------> a=2

ii. -1 = 2b-3 -------> 2 = 2b ------> b = 1

iii. 2(3)+3 = m -------> 6+3 = m -------> m=9

Hope this helps!!! :D

5 0
3 years ago
Can someone help me please
Lelechka [254]

Answer:

Step-by-step explanation:

6 0
3 years ago
 2x- 3y=9   5x+3y=12   How would i solve this? I dont understand this and i really need help with it!Also I have to graph the an
dedylja [7]
\begin{cases} 2x- 3y=9 \\5x+3y=12 \end{cases}\\ + \ \ ------- \\ 7x=21 \ \ /: 7\\ \\x=\frac{21}{3}\\ \\ x=3 \\ \\2x- 3y=9

2*3-3y=9\\ \\6-3y =9\\ \\-3y=9-6\\ \\-3y=3 \ \ / :(-3)\\ \\x=-1\\ \\ \begin{cases} x=3\\y= -1 \end{cases}

graph\\ \\\begin{cases} 2x- 3y=9 \\5x+3y=12 \end{cases}\\ \\ \begin{cases} - 3y=-2x+9\ \ /:(-3) \\ 3y=-5x+12 \ \ /:3 \end{cases}\\ \\ \begin{cases} y= \frac{2}{3}x-3 \\ y=-\frac{5}{3}x+4 \end{cases}


7 0
3 years ago
Please please please.
sesenic [268]
the possibilities are probably b, using the elimination method
4 0
3 years ago
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