Help me on this one please hellppp

The composite figure is made up of two congruent rectangular pyramids joined at their bases. What is the total volume of the com

Sedaia [141]

The volume of a rectangular pyramid is
V = (1/3) A*h
where
A = the area of the rectangular base
h = the height

The two pyramids are congruent in volume.
The volume of one pyramid is
(1/3)*(2*7.5)*(6) = 11
The volume of the composite figure is 2*11 = 22

Answer: 22

8 0

3 years ago

Read 2 more answers

HELP ME PLZ ASAPPPPPP

boyakko [2]

Answer:

$(x,y) =(-4,-3)$ --- Vertex

$x = -4$ --- Axis of symmetry

Step-by-step explanation:

Given

$y = -6(x + 4)^2 - 3$

Solving (a): The vertex

For an equation written in

$y = a(x - h)^2 + k$

The vertex is:

$(x,y) = (h,k)$

By comparison:

$y = a(x - h)^2 + k$ and $y = -6(x + 4)^2 - 3$

$-h =4$ $k = -3$

$h =-4$ $k = -3$

So, the vertex is:

$(x,y) =(-4,-3)$

Solving (b): The axis of symmetry

For an equation written in

$y = a(x - h)^2 + k$

The axis of symmetry is:

x = h

In (a):

$h =-4$

So:

$x = -4$

5 0

2 years ago

!!!!!!! I NEED THE WORK PLS ILL GIVE BRAINLIST!!!

dexar [7]

Answer:

1. 4 and 4sqrt2

2. 6sqrt2 and 6sqrt2

3. 5 and 5sqrt2

4. 5sqrt2 and 5sqrt2

5. 6 and 6

6. 8 and 8sqrt2

7. sqrt3 and sqrt6

8. sqrt2 and sqrt4

Step-by-step explanation:

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=2a%20%7B%20%7D%5E%7B2%7D%20b%20%7B%7D%5E%7B2%7D%20-%207ab%20-%2030" id="TexFormula1" title="2a

yarga [219]

Answer:

(ab - 6)(2ab + 5)

Step-by-step explanation:

Assuming you require the expression factorised.

2a²b² - 7ab - 30

Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term

product = 2 × - 30 = - 60 and sum = - 7

The factors are - 12 and + 5

Use these factors to split the ab- term

= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )

= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term

= (ab - 6)(2ab + 5) ← in factored form

5 0

2 years ago

HELP! WILL AWARD BRAINLIEST TO WHOEVER ANSWERS BOTH PARTS CORRECTLY!!

rewona [7]

check the picture below.

now, we're assuming the trapezoid is an isosceles trapezoid, namely AD = BC, and therefore the triangles are twins.

incidentally, b is the height of the trapezoid and likewise is also the altitude or height of the concrete triangle.

so we can simply get the area o the trapezoid, notice the bottom base is a+185+a, and then get the area of the concrete triangle and subtract the triangle from the trapezoid, what's leftover is just the vegetation area.

$\bf \begin{cases} a=283\cdot cos(80^o)\\ a\approx 49.14\\ --------\\ b=283\cdot sin(80^o)\\ b\approx 278.70 \end{cases}\\\\ -------------------------------\\\\ \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{bases}{parallel~sides}\\ h=height\\ ----------\\ x=185\\ y\approx \stackrel{a+185+a}{283.28}\\ h\approx\stackrel{b}{278.70} \end{cases} \\\\\\ A=\cfrac{278.70(185+283.28)}{2}\implies A\approx 65254.818$

so that's the area of the trapezoid, now let's get the area of the triangle.

$\bf \stackrel{triangle}{\cfrac{1}{2}(185)(b)}\implies \cfrac{1}{2}(185)(278.70)\qquad \approx 25779.80\\\\ -------------------------------\\\\ \stackrel{\textit{area for vegetation}}{\stackrel{\textit{area of trapezoid}}{65254.818}~~-~~\stackrel{\textit{area of triangle}}{25779.80}}\implies 39475.018$

since we know 36 yd² cost 12 bucks, then how much will it be for 39475.018 yd²?

$\bf \begin{array}{ccll} yd^2&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 36&12\\ 39475.018&x \end{array}\implies \cfrac{36}{39475.018}=\cfrac{12}{x}\implies x=\cfrac{39475.018\cdot 12}{36} \\\\\\ x\approx 13158.339\overline{3}$

3 0

2 years ago