Answer:
The reasonable range for the population mean is (61%, 75%).
Step-by-step explanation:
The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.
The mean of the sampling distribution of sample proportion is,
.
One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

Given:
n = 150
= 0.68
The critical value of <em>z</em> for 95% confidence level is:

Compute the 95% confidence interval for proportion as follows:


Thus, the reasonable range for the population mean is (61%, 75%).
Answer:
Equal 2 payments of 17.50$.
-5║4y-11║-3=12
-5║4y-11║-3 +3=12+3
- 5║4y-11║=15
-5/5║4y-11║=15/-5
║4y-11║=-3
4y-11=-3 -5║4y-11║-3=12
4y-11+11=-3+11 -5║4(2)-11║-3=12
4y=8 -5║-3║-3=12
4y/4=8/4 -5 (3)-3=12
y=2 -18≠12
4y-11=3 -5║4y-11║-3=12
4y-11+11=3+11 -5║4(7/2)-11║-3=12
4y=14 -5(3)-3=12
4y/4=14/4 -18≠ 12
y=7/2
No solutions
$1.14 1.40 x 0.8=1.12 1.4+ 1.12=1.52 * 0.25 = 1.14
Answer c=12 bellow is a step by step explanation hope it helps