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2 years ago

Calculate the number of boxes that can fit along the length of the boxes

Mathematics

1 answer:

GuDViN [60]2 years ago

7 0

Answer:

Can you send a picture so I can solve it?

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If lateral surface area of cube is double then the ratio of volume of new cube to original cube

Solnce55 [7]

Answer:

2√2

Step-by-step explanation:

The area ratio is the square of the side length ratio, so the ratio of side lengths is √2.

The volume ratio is the cube of the side length ratio, so the new cube has a volume that is (√2)³ times that of the original.

The volume ratio is 2√2.

3 0

2 years ago

Please help if you can. If possible please type how you got the answer so I can remember it next time I get a question like this

Gre4nikov [31]

Answer:

(2,3)

Step-by-step explanation:

I did this by using the equation that was given. y=x+1.

This mean that the starting point would be the coordinate (0,1) and the x is the slope, which means that from coordinate (0,1) I will go up one and one to the right until I intersected with coordinate (2,3).

8 0

2 years ago

Read 2 more answers

4f2 + 3h - g+f

Bas_tet [7]

Answer:

can't be simplified or you can add you get the answer

4 0

2 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

2 years ago

Evaluate the following functions at x = 10 q(x)=x^2-2x+2

Oduvanchick [21]

Answer:

Step-by-step explanation:

given:x=10

Evaluating,

(10)²-2(10)+2

=100-20+2

=80+2

=82

Pls mark me brainliest

5 0

2 years ago

Calculate the number of boxes that can fit along the length of the boxes​

Calculate the number of boxes that can fit along the length of the boxes