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ladessa [460]
2 years ago
5

PLZ HELP ME!!!!!! Help Is Urgent!!!!!!!!!

Mathematics
1 answer:
nordsb [41]2 years ago
3 0

Answer:

53% or 0.53 or 53/100

Step-by-step explanation:

You might be interested in
what is the first step used in solving this equation 2x+9y=28 and 3x-3y=14. Identify the variable that will be solved for when y
umka2103 [35]

Answer:

Multiply the second equation's terms by 3. Solve for x.

Step-by-step explanation:

You will get:

2x+9y=28

9x-9y=42

Add them to get:

11x=70.

You can solve from there.

7 0
3 years ago
After diving 86 feet below the surface, a diver ascends at 4 feet per minute. After 12 minutes pass, where is the diver located
Gemiola [76]
One possible way:
-86+(4*12)=-38
-86 is the number where the diver is. 86 feet below the surface.
4*12 is the total number of feet he has ascended in 12 minutes.
Because he is ascending, so you add 4*12 (or 48) to -86.
The answer is -38, meaning he's 38 feet below the surface.

The diver is now 38 feet below the surface.

Hope this helps.
7 0
3 years ago
What is the square root of negative 64?
aleksandrvk [35]
The answer should be 8 i
4 0
3 years ago
Read 2 more answers
"let v be the event that a computer contains a virus, and let w be the event that a computer contains a worm. suppose p(v) = 0.1
morpeh [17]

Here we might have to find p(v intersection w) and for that we use the following formula

p(v U w) = p(v)+p(w)-p(v intersection w)

And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .

Substituting these values in the formula, we will get

0.14 = 0.13 +0.04 -p(v intersection w)

p(v intersection w) =0.13 +0.04 -0.14 = 0.03

So the required answer of the given question is 0.03 .

7 0
2 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
Read 2 more answers
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