Answer:
11 inches
Step-by-step explanation:
V(cylinder) = πr²·h
2797.74 = 81π·h
h = 2797.74 ÷ 81π
h ≈11
First, you distribute 0.8 through the parentheses by multiplying 0.8 by s and -12, which gets you to 0.8s-9.6. Now, the equation is changed to 0.3s+0.8s-9.6=33.3. Then, you add like terms (add the two numbers with the s) by doing 0.3s+0.8s which gets you to 1.1s-9.6=33.3, all thats left is adding 9.6 on both sides which gets you to 1.1s=42.9. Now finally, you divide 42.9 by 1.1 and you get 39. The value of s in the equation is 39.
Answer:
2
Step-by-step explanation:
Order of operations is not as applicable in this situation because we're just dealing with addition and subtraction. This is a simple case of plugging in values for the given expression.
x = 3
z = 4
So it becomes...
3 + 3 - 4
6 - 4
2
So with the given expression of x + x - z and the given values of x = 3 and z = 4, the expression should sum to: 2
check the picture below.
so the triangular prism is really just 3 rectangles and 2 right-triangles,
now, we know the base of one of the triangles is 2.6, what's its height?
since it's a right-triangle, we can simply use the pythagorean theorem to get "h".
so, we can now, simply get the area of both of the triangles and the three rectangles and sum them up, and that's the area of the triangular prism.
![\bf \stackrel{two~triangles}{2\left[ \cfrac{1}{2}(2.6)(4.5) \right]}~~+~~\stackrel{rectangle}{(2.6\cdot 4.3)}~~+~~\stackrel{rectangle}{(4.3\cdot 3.9)}~~+~~\stackrel{rectangle}{(4.3\cdot 5.2)} \\\\\\ 11.7+11.18+22.36\implies \blacktriangleright 45.24 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Btwo~triangles%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.6%29%284.5%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%282.6%5Ccdot%204.3%29%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%284.3%5Ccdot%203.9%29%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%284.3%5Ccdot%205.2%29%7D%0A%5C%5C%5C%5C%5C%5C%0A11.7%2B11.18%2B22.36%5Cimplies%20%5Cblacktriangleright%2045.24%20%5Cblacktriangleleft)
Answer:
4c² + 11cd + 5d
Step-by-step explanation:
To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
