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3 years ago

REAAAALLLLY NEED HELP

2 answers:

6 0

If you think about it, the question is asking us to find the greatest common factor, or GCF, of the two numbers, 24 and 18.
First, find all of the factors of 24.
The factors are: 1, 2, 3, 4, 6, 8, 12, 24
Next, find the factors of 18.
The factors are: 1, 2, 3, 6, 9, 18
List out all of the factors that both of the numbers have.
The factors are: 1, 2, 3, 6
Whichever is the greatest of these numbers is the GCF.
The GCF is 6, so the greatest number of groups he can make and still be able to win is 6.
Hope this helps!

yanalaym [24]3 years ago

6 0

All you have to do with this question is find the GCF (Greatest Common Factor). You can do this by listing out all of the factors for each number.

For 18) 1, 2, 3, 6, 9, 18
For 24) 1, 2, 3, 4, 6, 8, 12, 24

Then you find the largest number that both share, so for this particular problem that would be 6.

So your final answer would be that Alex can make a maximum of 6 groups to have a chance at winning the prize.

If you need further explanation, just let me know :)

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A biker travels at a rate of 20 miles per hour. Calculate

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Answer:

60 miles

Step-by-step explanation:

20 miles times 3

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3 years ago

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The dividend is a factor of 60. The divisor is a factor of 18. The quotient is a multiple of 3. Use the numbers to find one poss

Diano4ka-milaya [45]

Answer:

A possible solution is 60/2 = 30

Step-by-step explanation:

The given parameters are;

The dividend is a factor of 60

The divisor is a factor of 18

The quotient is a multiple of 3

The dividend is the amount divided

The dividend is the number that is dividing the dividend

The quotient is the result of the division operation

The given numbers to use are 60, 2, 30, and 18

Therefore one possible solution is 60/2 = 30

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The divisor = 2 which is a factor of 18 (2 × 9 = 18)

The quotient = 30 which is a multiple of 3 (3 × 10 = 30)

6 0

2 years ago

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Harrizon [31]

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2 and I do not play it.

Step-by-step explanation:

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2 years ago

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Víctor claims that when 1/6 is divided by a fraction the result will always be greater than 1/6 find an example of a fraction th

Naddik [55]

Answer:

Step-by-step explanation:

Choose a random fraction less than 1. I will choose 1/4.

1/6 ÷ 1/4 = 1/6 × 4/1 = 4/6 = 2/3

2/3 > 1/6 so this example supports his claim.

Now chose a fraction greater than 1. I will choose 4/3

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3/24 < 1/6 so this contradicts his claim

6 0

2 years ago

Ksju [112]

Answer:

We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

Step-by-step explanation:

We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml.

A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0

Let $\mu$ = mean contents of cola bottles.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 300 ml {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}

Alternate Hypothesis, $H_A$ : $\mu$ < 300 ml {means that the mean contents of cola bottles is less than the advertised 300 ml}

The test statistics that will be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean contents of cola bottle = $\frac{\sum X}{n}$ = 299.03 ml

$\sigma$ = population standard deviation = 3 ml

n = sample of bottles = 6

So, test statistics = $\frac{299.03-300}{\frac{3}{\sqrt{6} } }$

= -0.792

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

8 0

3 years ago