See diagram
I wrote that the degrees are 70 each because it is isocolese and 140/2=70
a.
to solve for the diagonal, I'm going to use trig to find the height and the base then use pythagorean theorem to find the diagonal
so
see I've drawn an auxiliry line to make a right triangle on the leftmost side
so
we want to find the height and base
sin(70°)=h/7
so 7sin(70°)=h≈6.57785
cos(70°)=base/7
so 7cos(70°)=base≈2.39414
now
the entire long base is 22, so that big triangle with the diagonal as the hyptonuse is 22-2.39414=19.6059
use pythagorean theorem, like 6.57785²+19.6059²=diagonal²
we get that the diagonal is about 20.68ft
b.
we got that the base was 7cos(70°)
2 of those bases so 22-14cos(70°)=17.2117ft or rounded 17.21ft
a. 20.68ft
b. 17.21ft
Answer:
111 / 190
Step-by-step explanation:
Total biscuits = 20
Plain, P = 12
Chocolate, C = 5
Currant, K = 3
Assume without replacement :
Probability that biscuit are of the same type :
P(plain) :
12 / 20 * 11 / 19 = 132 / 380
P(chocolate) :
5/ 20 * 4 / 19 = 20/ 380
P(currant) :
3/20 * 2 /19 = 6 / 380
Therefore,
Probability that biscuit is of the same type :
P(plain) + P(chocolate) + P(currant)
132/380 + 20/380 + 6/380
158 / 380 = 79 / 190
Therefore, probability that biscuit aren't of the same type :
1 - P(biscuit is of same type)
1 - 79/190
(190 - 79) / 190
111 / 190
Answer:i dont know
Step-by-step explanation:
Here is the answer to the given question above. Given that there are a total of 18 students and 5/9 of the students have pets, let us divide 18 by 9 to see how many students have pets. So the answer would be 2. Since it is 5 out of 9, we multiply 2 by 5 and we get 10. Therefore, the answer is 10 students. Hope this answer helps.
Answer:
Step-by-step explanation:
We have the polynomial
( 1 )
To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials

we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have
and if we sum we obtain

that is what we was looking for
I hope this is useful for you
regards