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natima [27]
2 years ago
14

Which graph represents a function? 1 ty 1y 1y o Intro Done

Mathematics
1 answer:
WARRIOR [948]2 years ago
7 0
The graph that represents a function is the last graft on the screen (pic shown below)

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-10% because there is only one 2 in the 10 numbers. hope this helps
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3 years ago
Enter two million, eighty-seven thousand, three hundred four.
Ede4ka [16]

Answer:

2,087,304..........

8 0
3 years ago
Factor the following polynomial completely.<br><br>y squared plus 5 zy plus 4 z squared<br><br>​
sweet [91]

Answer:

(y + z)(y + 4z)

Step-by-step explanation:

{y}^{2}  + 5zy + 4 {z}^{2}  \\  =  {y}^{2} + zy + 4zy + 4 {z}^{2}  \\  = y(y + z) + 4z(y  + z) \\  = (y + z)(y + 4z)

7 0
3 years ago
A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the
Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

25% of all adults had used the Internet for such a purpose

This means that \pi = 0.25

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

What is the required sample size for the new study?

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}

\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2

n = 800.3

Rounding up:

The required sample size for the new study is 801.

4 0
2 years ago
1. x² + 2xy – 7 xy + 4y?<br>Input your answer here:​
viktelen [127]

collect the like terms:

Solution: x^2-5xy+4y

P.S

get the photo math app. :)

Hope that helps.

6 0
3 years ago
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