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2 years ago

Which graph represents a function? 1 ty 1y 1y o Intro Done

Mathematics

1 answer:

WARRIOR [948]2 years ago

7 0

The graph that represents a function is the last graft on the screen (pic shown below)

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Suppose you start an annuity where you invent$2,000 at the beginning or each year and 4% interest is paid at the end of the year

dimulka [17.4K]

I believe $80 dollars would be 4% of 2,000

7 0

3 years ago

Read 2 more answers

A drawer contains 4 red socks, 7 white socks, and 11 blue socks. Without looking, you draw out a sock and then draw out a second

Nana76 [90]

Total socks = 4 + 7+ 11 = 22
Red = 4
White = 7

P(red, then white) = (4/22)(7/21) = 2/33

Answer: 2/33

8 0

3 years ago

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

A theatre ticket costs £37 plus a booking fee of 4%.<br>What is the total price of the ticket?

Studentka2010 [4]

Answer:

£38.48

Step-by-step explanation:

First, we have to find what 4% of 37 is, so our equation is:

37 x 0.04 = 1.48

Then we have to add that 4% to the original cost:

1.48 + 37 = 38.48

So the total price of the theatre ticket is £38.48

6 0

3 years ago

Total surface area of this shape

skelet666 [1.2K]

Answer:

6 * 10 * 6

Step-by-step explanation:

6 0

3 years ago