Answer:
The correct answer is option 3.
Explanation:
2A → B + C
First trial ;
[A] = x , Rate of the reaction = R
Rate law of the reaction can be written as:
![R=k[x]^a](https://tex.z-dn.net/?f=R%3Dk%5Bx%5D%5Ea)
..[1]
Second trial ;
[A] = 3x , Rate of the reaction = R' = 9R
Rate law of the reaction can be written as:
![R'=k[3x]^a](https://tex.z-dn.net/?f=R%27%3Dk%5B3x%5D%5Ea)
![9R=k[3x]^a](https://tex.z-dn.net/?f=9R%3Dk%5B3x%5D%5Ea)
..[2]
[1] ÷ [2]
![\frac{R}{9R}=\frac{k[x]^a}{k[3x]^a}](https://tex.z-dn.net/?f=%5Cfrac%7BR%7D%7B9R%7D%3D%5Cfrac%7Bk%5Bx%5D%5Ea%7D%7Bk%5B3x%5D%5Ea%7D)
a = 2
Rate of the reaction : ![R=k[A]^3](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E3)
The order of the reaction is 2. This is because in the rate law expression the the power of the concentration of reactant A id 2.
The answer is TiBr4 which is the formula
Answer:
massive flooding occurs in may at this location
Explanation:
i did the quiz idk if its right though :/
Answer:
Percentage recovery of acetylferrocene = 81.6%
Explanation:
Mass of the sample mixture = 22.092 g
Ratio of mixture of acetylferrocene and ferrocene = 1 : 1
This means that the sample conatains equal amounts of acetylferrocene and ferrocene.
Therefore the mass of each sample in the mixture = 22.092 g / 2 = 11.046 g
Mass of acetylferrocene recovered = 9.017 g
Percentage recovery of acetylferrocene = (mass of recovered/ mass in sample) * 100%
Percentage recovery of acetylferrocene = (9.017 g / 11.046 g) *100%
Percentage recovery of acetylferrocene = 81.6%
