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s344n2d4d5 [400]
3 years ago
11

How to solve -22-(6)(-9)/3

Mathematics
2 answers:
lana [24]3 years ago
8 0

Answer:

-4

Step-by-step explanation:

-22-(6)(-9)/3

= -22 -(6) (-3)

= -22 +18

= -4

maria [59]3 years ago
3 0

Answer:

-4

Step-by-step explanation:

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A 18 foot ladder is leaning against a wall as shown
Inga [223]
I'm guessing the diagram shows a ladder leaning against a wall, making a right angle triangle with respect to the ground and the wall.

So, the wall's height is going to be the 'h', which will also be the 'opposite side' from the angle <span>ϴ which is made from the ladder and the ground.
</span>The ladder's length (18 foot) is going to be the 'hypotenuse' side and the other remaining side will be the 'adjacent'.

Now, once you've sorted out which side is which, we have to find the h (opp), and according to  SOH CAH TOA, we will choose Sin<span>ϴ = opp/hyp.
</span>so Sinϴ = h/18....now we gotta find h, so 'cross multiply' the equation to get  h = 18 x sin<span>ϴ.
</span>
To find angle ϴ, simply take the inverse of Sinϴ= h/18... and you'll get ϴ =  sin-1 (sin inverse) h/18

Hope this helps



6 0
3 years ago
Why isnt 40 divisable by 7 ?
stealth61 [152]

Actually, 40 is divisible by 7. Any number is divisible by 7. However, 7 does not go into forty evenly. Your quotient would have a remainder since 7 cannot go into 40 an even number of times.

7 goes into 40 5 times evenly (7x5=35) 40-35 is five, so 40 divided by 7 is 5  (remainder 5)

~theLocoCoco

6 0
3 years ago
What's the answer ????
faust18 [17]
The answer is (-4, 5).
8 0
3 years ago
Calculus 2: I need help with u substitution and intergration by parts. Can someone help me understand the concept?​
snow_lady [41]

Computing an integral by substitution is the reverse of the chain rule for computing the derivative. Substitution is intended to rewrite a complicated-looking integral involving the derivative of some component expression as another much simpler integral. For example, if u=f(x), then \mathrm du=f'(x)\,\mathrm dx and

\displaystyle\int f(x)f'(x)\,\mathrm dx=\int u\,\mathrm du

###

Integration by parts is the reverse of the product rule for derivatives:

(f(x)g(x))'=f'(x)g(x)+f(x)g'(x)\implies f(x)g'(x)=(f(x)g(x))'-f'(x)g(x)

Integrating both sides with respect to x gives

\displaystyle\int f(x)g'(x)\,\mathrm dx=\int(f(x)g(x))'\,\mathrm dx-\int f'(x)g(x)\,\mathrm dx

\displaystyle\int f(x)g'(x)\,\mathrm dx=f(x)g(x)-\int f'(x)g(x)\,\mathrm dx

###

Personally, I think the best way to grasp the idea behind the two methods is to practice. You start to notice patterns to the point where knowing which is the "right" method to use becomes second nature.

4 0
3 years ago
Explain how you could use a number line to determine -5 -(-3)<br><br> What is the difference?
siniylev [52]

Answer:

-2

Step-by-step explanation:

Start on -5 on the left side of the number line, jump from -5 three times to the right of the number line since ( - - ) means to add. As you jump draw "bridges" and by the time you have completed the amount of jumps you have to do you'll end up with a difference of -2.

8 0
3 years ago
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