Question

Can someone help me with these questions. Even if you can only help me with one, it would be appreciated.

Answer 1

Try these solutions:

Task 1.

a) the required angle is arctan(CG/AC);

b) according to the condition CG=AE=11.4 (cm.);

c) BC=EH=9.6 (cm.), then

$AC=\sqrt{AB^2+BC^2}=\sqrt{18.4^2+9.6^2}=\sqrt{430.72} (cm.);$

d) the required angle is:

$arctan\frac{CG}{AC}=arctan\frac{11.4}{\sqrt{430.72}}=arctan(0.549297)=28.5=29$

Answer: 29°

Task 2.

a) the required angle is EFV (see the attached picture): arctan(EV/FE);

b) to calculate FE: FE=0.5AB=7.25 (cm.);

c) to calculate EV:

$EV=\sqrt{DV^2-DE^2} =\sqrt{17.2^2-(14.5/\sqrt{2})^2}=13.80996 (cm.);$

d) to calculate the required angle:

m(∠EFV)=arctan(13.80996/7.25)=arctan(1.9048)≈62.302°=62°.

Answer: 62°