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Korvikt [17]
2 years ago
14

What is fake love ??????(|_|)​

Chemistry
1 answer:
Kruka [31]2 years ago
5 0

Answer:

They're emotionally distant. In a relationship, fakers have a tendency to be non-communicative. ...

Always willing to throw in the towel. Conflict happens in every relationship. ...

They don't meet you halfway. Are you always the one to plan things? ...

Unconcern. ...

That gut feeling.

Explanation:

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What are two processes that result in rocks being broken down into smaller pieces !?
Snowcat [4.5K]
<span>"Chemical weathering and physical weathering" would be the correct answer

Chemical weathering breaks down the bonds holding the rocks together, and the physical weathering will crush and break them apart.</span>
7 0
3 years ago
Natural gas is primarily composed of ________. natural gas is primarily composed of ________. methane sulfur dioxide nitrogen ox
umka21 [38]
Natural  gas  is primarily composed of   methane (CH4)

 N
atural  gas  is a naturally  occurring  hydrocarbon  mixture  which  is  primarily  composed of Methane(CH4),  but it  also  contains ethane,propane and  heavier hydrocarbon. In addition  it  contain small amount  of nitrogen, carbon dioxide,hydrogen sulfide and traces amount of water.

7 0
3 years ago
Redi placed pieces of meat in several jars. He divided the jars into two groups. He covered the first group of jars with fine cl
OlgaM077 [116]

Answer:

Experiment Question, Independent & Dependent Variable, Null & Alternate Hypothesis

Explanation:

Experiment Question : Whether fine cloth coverage over chicken jars effect flies & their eggs in ambience ?

Independent Variable : The causal variable, ie cloth cover existence on the chicken jar

Dependent Variable : The resultant variable, ie presence of flies & their eggs near jar, meat

Null Hypothesis [H0] : Cloth cover on chicken jar doesn't effects flies' & eggs' presence around jar, chicken.

Alternate Hypothesis [H1] : Cloth cover on chicken jar effects flies' & eggs' presence around jar, chicken.

6 0
3 years ago
Help me find the IUPAC names please
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3)4- chloro alanine

8 0
2 years ago
Be sure to answer all parts. one of the most important industrial sources of ethanol is the reaction of steam with ethene derive
lions [1.4K]

Answer: 2.17x10⁻³ atm

Explanation:

First, we must write the balanced chemical equation for the process:

C₂H₄(g) + H₂O(g) ⇌ C₂H₅OH(g)

The chemical reactions that occur in a closed container can reach a state of <u>chemical equilibrium</u> that is characterized because the concentrations of the reactants and products remain constant over time. The <u>equilibrium constant</u> of a chemical reaction is the value of its reaction quotient in chemical equilibrium.

The equilibrium constant (K) is expressed as <u>the ratio between the molar concentrations (mol/L) of reactants and products.</u> Its value in a chemical reaction depends on the temperature, so it must always be specified.

<u>We will use the the equilibrium constant Kc of the reaction to calculate partial pressure of ethene.</u> The constant Kc for the above reaction is,

Kc = \frac{[C_{2} H_{5}OH]}{[H_{2}O][C_{2} H_{4}]}

According to the law of ideal gases,  

PV = nRT  

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the gas constant (0.082057 atm L / mol K) .

We can use the ideal gas law to determine the molar concentrations ([x] = n / V) from the gas pressures of ethanol and water, assuming that all gases involved behave as ideal gases. In this way,

PV = nRT → P = (n/V) RT → P = [x] RT → [x] = P / RT

So,  

[C_{2} H_{5}OH] = \frac{200 atm}{0.082057 \frac{atm L}{mol K} x 600 K } = 4.06 \frac{mol}{L}

[H_{2}O] = \frac{400 atm}{0.082057 \frac{atm L}{mol K} x 600 K } = 8.12 \frac{mol}{L}

So, the molar concentration of ethene (C₂H₄) will be,

[C_{2} H_{4}] = \frac{[C_{2} H_{5}OH]}{[H_{2}O] x Kc} = \frac{4.06 \frac{mol}{L} }{8.12 \frac{mol}{L}x9.00 x 10^{3} \frac{L}{mol} } = 5.56 x 10^{-5}\frac{mol}{L}

Then, according to the law of ideal gases,

P_{C_{2} H_{4}} = [C_{2} H_{4}]RT = 5.56 x 10^{-5} \frac{mol}{L}  x 0.082057 \frac{atm L}{mol K} x 600 K = 2.17x10^{-3} atm

So, when the partial pressure of ethanol is 200 atm and the partial pressure of water is 400 atm, the partial pressure of ethene at 600 K is 2.17x10⁻³ atm.

7 0
3 years ago
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