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anastassius [24]
2 years ago
6

The stock concentration of NaOH is 0.5M. 0.5M = 0.500mol/1.0L.

Chemistry
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:a) 0.1 mole. b) 4g. c) 2% d)  196 mL

Explanation: in 200mL , 0.1mole

mw NaOH = 40g/mol —> 4g in 0.1 mole

4g in 200mL so 2g in 100mL

density NaOH = 1g/mL so if 4g in 200 mL,  4mL , 196 mL water

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<u>Answer:</u> The percentage yield of water is 9.5 %

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We are given:

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By Stoichiometry of the reaction:

2 moles of hydrogen gas reacts with 1 mole of oxygen gas

So, 14 moles of hydrogen gas will react with = \frac{1}{2}\times 14=7mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent

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By Stoichiometry of the reaction:

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To calculate the percentage yield of water, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of water = 1.33 moles

Theoretical yield of water = 14 moles

Putting values in above equation, we get:

\%\text{ yield of water}=\frac{1.33mol}{14mol}\times 100\\\\\% \text{yield of water}=9.5\%

Hence, the percent yield of the water is 9.5 %.

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