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2 years ago

The stock concentration of NaOH is 0.5M. 0.5M = 0.500mol/1.0L.

Chemistry

1 answer:

valentinak56 [21]2 years ago

5 0

Answer:a) 0.1 mole. b) 4g. c) 2% d) 196 mL

Explanation: in 200mL , 0.1mole

mw NaOH = 40g/mol —> 4g in 0.1 mole

4g in 200mL so 2g in 100mL

density NaOH = 1g/mL so if 4g in 200 mL, 4mL , 196 mL water

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2 years ago

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artcher [175]

Explanation:

The given data is as follows.

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$T_{2}$ = $1220 ^{o}C$ = (1220 + 273) K = 1493 K

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$log(\frac{P_{2}}{P_{1}}) = \frac{\Delta H_{vap}}{2.303R}[\frac{1}{T_{1}} - \frac{1}{T_{2}}$

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Beer Lambert's law relates the absorbance (A) of a substance to its concentration (c) as:

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A plot of 'A' vs 'c' gives a straight line with slope = εl

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