Answer:
We need 6.71 moles of O2 (or 214.7 grams of O2) to react with 8.95 moles of Al
Explanation:
Step 1: Data given
Number of moles of Al = 8.95 moles
Step 2: The balanced equation
4Al + 3O2 → 2Al2O3
Step 3: Calculate moles number of moles O2 needed to react with Al
For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3
For 8.95 moles Al we need 3/4 * 8.95 = 6.71 moles O2
There will 8.95/2 = 4.48 moles Al2O3 be produced
We need 6.71 moles of O2 to react with 8.95 moles of Al
Mass O2 = moles O2 * molar mass O2
Mass O2 = 6.71 moles * 32.0 g/mol
Mass O2 =214.7 grams O2
We need 214.7 grams of O2 to react with 8.95 moles Al