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insens350 [35]
3 years ago
6

____ handles are used to resize and image diagonally​

Computers and Technology
1 answer:
just olya [345]3 years ago
3 0

Answer:

Sizing handles in image editors

When working within an image editor, handles are small black boxes located at several points on the border of an image. They allow the user to increase the size horizontally, vertically, or diagonally, depending on their position.

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In the following four questions, we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the pa
pantera1 [17]

Answer:

1)we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Initially suppose there is only one link between source and destination. Also suppose that the entire MP3 file is sent as one packet. The TRANSMISSION DELAY is:

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2)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. The END TO END DELAY(transmission delay plus propagation delay) is

3.05 seconds

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we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. how many bits will the source have transmitted when the first bit arrives at the destination.

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we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose there are two links between source and destination, with one router connecting the two links. Each link is 5,000 km long. Again suppose the MP3 file is sent as one packet. Suppose there is no congestion, so that the packet is transmitted onto the second link as soon as the router receives the entire packet. The end-to-end delay is

6.1 seconds

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we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose that the MP3 file is broken into 3 packets, each of 10 Mbits. Ignore headers that may be added to these packets. Also ignore router processing delays. Assuming store and forward packet switching at the router, the total delay is

4.05 seconds

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we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose there is only one link between source and destination, and there are 10 TDM channels in the link. The MP3 file is sent over one of the channels. The end-to-end delay is

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Answer:

Following are the program to this question:

import java.util.*; //import package

public class Main //defining class

{

 public static void main(String[] args) //defining main method

 {

   int testedEmployee; //defining integer variable

   for(int i = 1;i<=52;i++) //defining loop that counts from 1 to 52  

   {

     testedEmployee = 1 + (int) (Math.random() * 30); //using random method that calculate and hold value

     System.out.print(testedEmployee+"\t"); //print value

     if(i%4 == 0)//defining codition thats checks value is divisiable by 4  

     {

       System.out.println(); //print space

     }

   }

 }

}

Output:

please find the attachment.

Explanation:

In the given java program, a class Main is declared, inside the class, the main method is declared, in which an integer variable "testedEmployee", is declared, in the next line, the loop is declared, that can be described as follows:

  • Inside the loop, a variable "i" is declared, which starts from 1 and stop when its value is 52, inside the loop a random method is used, that calculates the random number and prints its value.
  • In the next step, a condition is defined, that check value is divisible 4 if this condition is true, it will print a single space.

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