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Musya8 [376]
4 years ago
13

Does the following program represent an algorithm in the strict sense? Why or why not? Count=0 while count (count ! =5): count =

count + 2
Computers and Technology
1 answer:
zepelin [54]4 years ago
5 0
The answer is No. It doesn't program represent an algorithm in the strict sense. The process described will never terminate because the value of Count will never be 5. It doesn't not represent an algorithm and the process that has been described will never be terminate because the number will never be 5.
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Two boxes overlap if their interiors have at least one point in common. Give an O(n log n)-time algorithm that decides if there
GaryK [48]

Answer:

// Program is written in C++ programming language

// The program checks if two boxes overlap and prints both boxes

// Comments are used for explanatory purpose

// Program starts here

#include<bits/stdc++.h>

#include <graphics.h>

#include <conio.h>

// Define x and y axis

struct axis { int x, y; };

bool checkRect(Axis l1, Axis r1, Axis l2, Axis r2)

{ // l1, l2, r1 and r2 represent the left and right coordinates of both rectangles

// Check one rectangle is on left side of other

if (l1.x > r2.x || l2.x > r1.x) {

return false; }

// Check if one rectangle is above other

if (l1.y < r2.y || l2.y < r1.y) {

return false; }

return true;

}

// Main Method begins here

int main()

{

// Declare integer variables to enter rectangle coordinates

// For rectangle 1

int left1, left2, right1, right2;

cout<<"Enter First rectangle coordinates: "<<"\n";

cout<<"Top Left: "<<"\n";

cin>>left1;

cout<<"Bottom Left: "<<"\n";

cin>>left2;

cout<<"Top Right: "<<"\n";

cin>>right1;

cout<<"Bottom Right: "<<"\n";

cin>>right2;

// For rectangle 2

int left3, left4, right3, right4;

cout<<"Enter Second rectangle coordinates: "<<"\n";

cout<<"Top Left: "<<"\n";

cin>>left3;

cout<<"Bottom Left: "<<"\n";

cin>>left4;

cout<<"Top Right: "<<"\n";

cin>>right3;

cout<<"Bottom Right: "<<"\n";

cin>>right4;

Axis l1 = {left1, left2}, r1 = {right1, right2};

Axis l2 = {left3, left4}, r2 = {right3, right4};

if (checkRect(l1, r1, l2, r2)) {

cout<<"The Rectangles Overlap"; }

else {

cout<<"Rectangles Don't Overlap";}

// Print Rectangle 1

rectangle (left1, right1, left2, right2);

// Print Rectangle 2

rectangle (left3, right3, left4, right4);

return 0;

}

5 0
3 years ago
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If you're using a computer, you can take a picture on a camera, copy the picture to your computer to upload to Brainly.

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8 0
4 years ago
Read 2 more answers
Answer the question ASAP please
RUDIKE [14]

Answer:

Shows the programming checking if num1 is greater than num2

Explanation:

So num1 and num2 are inputs

for you to code this you would need to put

num1=int(input("What is your first number? ))

and the same for num2 except change num1 for num 2 and first for second

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it will do this by using a code something like:

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But in this example if it greater it just ends

But if it was less than you would put

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elif num1<num2:

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So basically this code shows the computer checking if one number is greater than the other or not

3 0
3 years ago
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¿Qué creo que debe considerar una empresa para elegir ellugar en el cual va a desarrollar su actividad económica osu emprendimie
zhannawk [14.2K]

Answer:

sorry I don't speak that language

8 0
3 years ago
Henry is designing a document for his architecture project. In which order should Henry preform the different tasks that are req
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It is

Select an appropriate layout

Decide which current format...

Import or compose...

Proofread...

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4 0
3 years ago
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