We observe that 14 is 4 more than twice 5.
The scooter's rate is 14 mph.
The bicycle's rate is 5 mph.
_____
time = distance/rate
14/(2b +4) = 5/b . . . . . . let b represent the bicycle's speed in mi/h
14b = 10b +20 . . . . . . . .cross multiply
4b = 20 . . . . . . . . . . . . . subtract 10b
b = 5 . . . . . . . . . . . . . . . divide by 4. Same answer as above.
tried to do it on text but It was pretty hard
8. complementary angles = 90°
3x+3+10x-4 = 90
13x-1 = 90
13x = 91
so x = 91/13= 7
then K = 3(7)+3 = 24°
so L = 10(7)-4 = 70-4 = 66°
9. P is three less than twice of Q
so P = 2Q-3
supplementary angles = 180°
P+Q = 180
(2Q-3)+Q = 180
3Q-3 = 180
3Q = 183
so Q = 183/3 = 61°
then P= 2(61)-3 = 122-3 = 119°
10. B is two more than three times of C so B= 3C+2
complementary angles = 90°
B+C= 90
(3C+2)+C=90
4C+2=90
4C= 88
so C= 22°
then B = 3(22)+2= 66+2 = 68°
(z+2)= (z-3)(5/-3)
z+2 = 5z/-3 +5
-3= 2z/-3
9= 2z
9/2 = z
<span>You can check all the rates on the number line by finding the quotient between the top rate and the bottom rate given and make sure that all of your quotients are equal to the given rate. </span>
