The size conductor that should be used to supply each motor is 12 AWG and the size conductor that should be used for the feeder conductor is 1/0AWG.
<h3>Size conductor</h3>
a. Using NEC table 430.250
Running connect for 150HP connected to 460V = 21 A
Conductor size=25% current to 125% current (Increase)
Increase current=21×125/100
Increase current=26.25 A
Nearest standard conductor size using NEC table 310.15(B)(16)=25 A
Since the motor contain NEMA design code the conductor will be choosing from 75° column which means that the size conductor that should be used to supply each motor is 12AWG copper conductors.
b. Feeder conductor
Using NEC section 430.24 plus ampere rating of other motors
Running current
Using NEC Table 430.250
Running current=26.25+21+21+21+21+21
Running current=131.25 A
The value that is greater than 131.25 A under 75° column of NEC Table 310 (B)(16) is 150 A which means that the size conductor that should be used for the feeder conductor is 1/0 AWG conductors.
Therefore the size conductor that should be used to supply each motor is 12 AWG and the size conductor that should be used for the feeder conductor is 1/0AWG.
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Answer:
your answer is correct
Explanation:
You have the correct mapping from inputs to outputs. The only thing your teacher may disagree with is the ordering of your inputs. They might be written more conventionally as ...
A B Y
0 0 1
0 1 0
1 0 0
1 1 1
That is, your teacher may be looking for the pattern 1001 in the last column without paying attention to what you have written in column B.
Answer:
0.5274 lagging.
Explanation:
So, we are given the following data or parameters or information which is what we need in order to solve this kind of question effectively. So, we have;
=> " For the given network:
ZR = 100 [Ω] , ZL = j124 [Ω], and ZC = - j89 [Ω]"
And we are asked to find the power factor. The power factor can be found or determined or calculated as;
7eq= 100 + j ( 24) (-89).
7eq = 124 × 89 - j89 × 100/ 100 + j35
7 eq= 133.81 L- 58.17.
Thus, the power factor is equal to;
=> Cos (58.17)= 0.5274 lagging.
Hence, the correct answer to this question is 0.5274 lagging.
Answer:
(D) Unlike traditional techniques, 3-D printing results in some wasted material.
Explanation:
3-D printing :
1. It is also known as additive manufacturing.
2. It can use for complex shape printing.
3.It is generally use in fashion areas.
4. In this printing method wasted material is very low as compare to traditional printing.
5.It is use CAD system for printing.
So the option D is correct.
(D) Unlike traditional techniques, 3-D printing results in some wasted material.