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OLga [1]
3 years ago
12

An inside measurement can be taken with a tape measure by

Engineering
1 answer:
Cerrena [4.2K]3 years ago
3 0

This is about method of taking inside measurement with a tape.

<u><em>Option A is the correct answer.</em></u>

  • Inside measurement is usually taken with the aid of an inside micrometer. This will give us an exact measurement. This is because when making use of an inside micrometer for inside measurement, the total length of the inside micrometer is equal to the overall length of whatever is being measured.

  • We have seen how the inside micrometer is used whereby the entire body is also included in whatever is being measured. Applying this same concept to using a tape, we can simply say that we will add the tape length to the measuring case to get the inside measurement.

  • From the definitions and comparisons above, we can see that we will have to add the length of the tape measure case when taking inside measurements and other options aside Option A are not correct.

Read more at; brainly.com/question/12709703

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If the specific surface energy for aluminum oxide is 0.90 J/m2 and its modulus of elasticity is (393 GPa), compute the critical
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Answer:

critical stress required for the propagation is 27.396615 ×10^{6} N/m²

Explanation:

given data

specific surface energy = 0.90 J/m²

modulus of elasticity E = 393 GPa = 393 ×10^{9} N/m²

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to find out

critical stress required for the propagation

solution

we will apply here critical stress formula for propagation of internal crack

( σc ) = \sqrt{\frac{2E\gamma s}{\pi a}}    .....................1

here E is modulus of elasticity and γs is specific surface energy and a is half length of crack i.e 0.3 mm  = 0.3 ×10^{-3} m

so now put value in equation 1 we get

( σc ) = \sqrt{\frac{2E\gamma s}{\pi a}}

( σc ) = \sqrt{\frac{2*393*10^9*0.90}{\pi 0.3*10^{-3}}}

( σc ) = 27.396615 ×10^{6} N/m²

so critical stress required for the propagation is 27.396615 ×10^{6} N/m²

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Answer:

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