Maybe it’s, I’m not 100% sure tho, 4/25
Solving a compound inequality for this solution gives solution as;
13 daytime cameras and 7 flash cameras or 7 daytime cameras and 13 flash cameras
<h3>How to solve inequality problems?</h3>
Let the number of daytime cameras be x
Let the number of flash cameras be y
Thus, we have;
x + y = 20 ------(1)
Now, daytime cameras costs 2.75 dollars and the flash camera costs 4.25 dollars and you want to spend between 65 and 75 dollars, inclusive. Thus, the inequality to represent this are;
2.75x + 4.25y ≥ 65 and 2.75x + 4.25y ≤ 75
Solving the 3 compound inequalities simultaneously, we can say that the approximate values of the numbers of cameras are;
13 daytime cameras and 7 flash cameras or 7 daytime cameras and 13 flash cameras
Read more about Inequalities at; brainly.com/question/25275758
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<span>3n-8+2(5n+3)=8n+5+4n first I will do the multiplication
3n-8+10n+6=8n+5+4n Now I will simplify
13n -2 = 12n +5 Now I will add 2 to both sides
13n = 12n + 7 then I subtract 12n from both sides
n = 7</span>
