When a genetic population follows Hardy-Weinberg Equilibrium (HW), it states that certain biological tenets or requirements must be met. Given so, then HW states that the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimal. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
So the problem states that homozygous dominant individuals (p^2) account for 60%, or 0.60. Thus the square root (sr) of p^2 = p or the dominant allele frequency in the population. So sr(p^2) = sr(0.60) -->
p = 0.775 or 77.5%
Homozygous recessive individuals (q^2) account for 20%, or 0.20. Thus sr(q^2) = q or the recessive allele frequency in the population. So sr(q^2) = sr(0.20) --> q = 0.447 or 44.7%
But since 44.7% + 77.5% = 122.2%, which is not equal to 1, we have a situation in which the allele frequencies do not match up, therefore this population cannot be determined using the Hardy-Weinberg Equation.
Scabs and Clots to help stop cuts and scrapes from bleeding.
The tumor suppressors allele is analogous to the brake pedal in a vehicle while cyclins are like the gas pedal. The tumor supressors regulate, negatively, the replication of cells. If the tumor supressor is mutated, this is analogous to the brake pedals of the vehicle being broken, This means that if two are broken, then the vehicle will be unable to stop and will continue moving. This same way, if tumor suppressors are mutated, the replication of cells will continue unregulated and casue a tumor.
Answer:
Partly correct, as it as guessed
Explanation:
<span>He is a carrier for color blindness and passes this Xc to his son</span>
