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Misha Larkins [42]
3 years ago
8

Please help me if you know this​

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0
First you have to subtract 1.3 from 0.75 which equals -0.55. Then you have to add 3/7 to 2 which equals 2 and 3/7. Then you divide 2 and 3/7 by -0.55 which equals 0.9785 and that’s your answer. Sorry I don’t know the answer for the second problem but I hope this helped.
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Please help to solve the 4th question
vichka [17]
The answer is 1/2 time
8 0
3 years ago
Read 2 more answers
(7t-2)-(-3+1)=-3(1-3t) how do you do this?
Sergeu [11.5K]
<h2>Greetings!</h2>

Answer:

t = \frac{3}{2}

Step-by-step explanation:

First, you need to complete the -3 + 1 and then expand the brackets

-3 + 1 = -2

7t -2 - (-2) = -3(1 - 3t)

Now expant the -3(1 - 3t) bracket

-3 * 1 = -3

-3 * -3t = 9t

7t - 2 - -2 = 9t - 3

The two negatives turn positive:

7t - 2 + 2 = 9t - 3

7t = 9t - 3

Move the -3 over to the oposite side, and also move the +7t over to the +9t, making it a negative:

3 = 9t - 7t

3 = 2t

Divide both sides by 2:

t = \frac{3}{2}

So the value of t is \frac{3}{2}


<h2>Hope this helps!</h2>
6 0
4 years ago
HELP PLEASEEEE THERES PICCTURESSS
LenKa [72]
I hate school so much <3
4 0
2 years ago
Read 2 more answers
Identify the lateral area and surface area of a right cone with a radius of 7 cm and a slant height of 15 cm. PLEASE HELP!!! A)L
Arisa [49]

Answer:

Step-by-step explanation:

a.  

L

=

329.9

c

m

2

;

S

=

373.9

c

m

2

.

b.  

L

=

659.7

c

m

2

;

S

=

483.8

c

m

2

.

c.  

L

=

659.7

c

m

2

;

S

=

813.6

c

m

2

.

d.  

L

=

329.9

c

m

2

;

S

=

483.8

c

m

2

.

Surface Area of a Cone:

In the three dimensional geometry, a cone is a shape that has a circular base and a lateral surface is associated with a vertex and the base.

The height of the cone is the length of a line segment that joins the base to the vertex of the cone.

The radius of the cone is the same as the radius of the base.

Surface area of a cone

(a) Lateral Surface Area

If  

l

and  

r

are the slant height and radius of a cone then its lateral surface area is given by the formula-

L

=

π

r

l

where  

L

is the lateral surface area of the cone

(b) Total surface area

It is the sum of the area of the circular base and the lateral surface area of the cone.

S

=

L

+

π

r

2

S

=

π

r

l

+

π

r

2

Where  

S

is the total surface area of the cone

Answer and Explanation:

Given that the radius and slant height of a right cone is  

7

c

m

and  

15

c

m

respectively

r

=

7

c

m

l

=

15

c

m

So the lateral surface area of the cone-

L

=

π

r

l

L

=

π

(

7

)

(

15

)

L

=

105

π

L

=

105

(

3.14159

)

L

=

329.866

L

≈

329.9

c

m

2

And the total surface area of the cone-

S

=

L

+

π

r

2

S

=

329.9

+

π

(

7

)

2

S

=

329.9

+

49

(

3.14159

)

S

=

329.9

+

153.937

S

=

483.83

c

m

2

So the lateral area and total area of a right cone are  

329.9

c

m

2

and  

483.8

c

m

2

respectively.

5 0
4 years ago
A ball is thrown into the air and its position is given by h ( t ) = − 6.3 t 2 + 53 t + 24 where h is the height of the ball in
nordsb [41]

Answer:

h'(t) = -12.6 t +53

Now we can set up the derivate equal to 0 and we have:

-12.6 t +53 = 0

And solving for t we got:

t = \frac{53}{12.6}= 4.206

For the second derivate respect the time we got:

h''(t) = -12.6

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

Step-by-step explanation:

For this case we have the following function:

h(t) = -6.3t^2 +53 t+24

In order to maximize this function we need to take the first derivate respect the time and we have:

h'(t) = -12.6 t +53

Now we can set up the derivate equal to 0 and we have:

-12.6 t +53 = 0

And solving for t we got:

t = \frac{53}{12.6}= 4.206

For the second derivate respect the time we got:

h''(t) = -12.6

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

8 0
4 years ago
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