Question

What are solutions to the equation below x^2 +3x-18=0

Answer 1

x^2+3x-18=0

(x+6)(x-3)

x=3,-6

Answer 2

You could plug it into a calculator to get your solutions or you could factor. Let's factor.

You need to find two numbers that when multiplied get you -18 and when added get you 3.

Let's get factors of -18:
1 × -18
2 × -9
3 × -6

The only factors that can get you that are -3 and 6.

(x-3)(x+6)=0

Set each factor equal to 0 and solve.
x-3=0
x=3

x+6=0
x=-6

Your solutions are 3 and -6.