To find the area of the shaded region you need find the area
of the shaded region and subtract the area of the unshaded region.
Area of a rectangle = width x length
A = (x + 10) x (2x + 5)
Next apply FOIL or
First Outer Inner Last
A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)
A= 2x2 + 5x + 20x + 50
A= 2x2 +25x +50
Area of a square= sides2
A= (x + 1)2
A= (x+1) (x+1)
Next apply FOIL or
First Outer Inner Last
A = (x *x) (1*x) (1*x) (1*1)
A = x2 + 1x + 1x +1
A= x2 + 2x +1
A= 2x2 +25x +50 - 2x2 +25x +50
A= 50x + 100
Answer:
y = 3x + 2
Step-by-step explanation:
The equation for two points on a line is generated from the straight line equation y = mx + b ---------------- eqn (i)
where m, the slope = (y2 - y1) / (x2 - x1)
therefore for (0,2) and (1,5) m = (5 - 2)/(1 - 0) = 3
This implies that eqn (i) can be rewritten as:
y = 3x + b ------------------- eqn (ii)
pickintg the point (0,2) and substituting into eqn (ii)
2 = 3(0) + b
this implies that b = 2
for confirmation with (1,5)
5 = 3(1) + b
b = 5 - 3 = 2
hence m = 3, b = 2
the equation is y = 3x + 2
Question 1: (0,2) because b value in mx+b is y-intercept
Question 2: plug in 4 for x you will get 1 so max is (4, 1)
Question 3: plug in -4 for x you will get -5 so min is (-4, -5)
Hope it helps :D
The width of the rectangle is 11.5
Huh this gives out no information to answer
