Answer:
For less than 7 uniforms.
Step-by-step explanation:
The first company she called charges $70 per uniform.
So, the cost of x uniforms will be $70x.
The second company she called charges $280 plus $30 per uniform.
So, the cost of x uniform will be $(280 + 30x).
Now, if the total cost of purchasing x number of uniforms from the first company is less than that from the second company then, we can write the inequality equation as
70x < 280 + 30x
⇒ 70x - 30x < 280
⇒ 40x < 280
⇒ x < 7
Therefore, for less than 7 uniforms the cost from the first company will be less than the cost from the second company. (Answer)
Answer:
C
Step-by-step explanation:
![y^2+4y-32=0\\(y+8)(y-4)=0\\y=4,-8](https://tex.z-dn.net/?f=y%5E2%2B4y-32%3D0%5C%5C%28y%2B8%29%28y-4%29%3D0%5C%5Cy%3D4%2C-8)
Therefore, the answer is C. Hope this helps!
So, if we look at the number pattern, we can see the numbers go up by 4.
The rule is Add 4.
So, to find the next two terms, we would add 4 to the last number shown, which is 15.
15 + 4 = 19
19 + 4 = 23
So, the next two terms are →19← and →23←.
Glad I could help, and good luck!
AnonymousGiantsFan
The graph is misleading because the year’s interval is not constant.
The first year to the second year, the gap is 1 year; in the second to the
third year, the gap is 2; in the third to the fourth year is 4; and the fourth
to the fifth year is 6.
Answer:
The answer to your question is: third option is correct.
Step-by-step explanation:
The third option is correct
4(-2)⁻²(4)⁻³
![\frac{4}{(2)^{2}(4)^{3}}}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B%282%29%5E%7B2%7D%284%29%5E%7B3%7D%7D%7D)