Answer:
See below.
Step-by-step explanation:
Draw segment OB.
In triangle OBC, points R and S are the midpoints of sides OC and BC, respectively. That makes RS parallel to OB.
In triangle OBA, points P and Q are the midpoints of sides OA and BA, respectively. That makes PQ parallel to OB.
Since segments RS and PQ are parallel to segment OB, then RS and PQ are parallel to each other.
Answer:
See explanation below
Step-by-step explanation:
BD - diagonal Added Construction
m∠CBD = m∠ADB Alternate Interior Angles Theorem
BD ≅ DB Reflexive Property
m∠A = m∠C Opposite ∠'s Congruent Theorem
ΔABD ≅ ΔCDB AAS or SAS
BC ≅ DA CPCTC
AC - diagonal Added Construction
m∠BCA = m∠CAD Alternate Interior Angles Theorem
AC ≅ CA Reflexive Property
m∠B = m∠D Opposite ∠'s Congruent Theorem
ΔABC ≅ ΔCDA AAS or SAS
AB ≅ CD CPCTC
Answer:
Y=1.88x
Step-by-step explanation:
x1=2 x2=3, y1=3.76 y2=5.64
(2, 3.76) (3, 5.64)
m(slope) =5.64-3.76/3-2
m=1.88
y-3.76=1.88(x-2)
y-3.76=1.88x-3.76
Y=1.88x
The answer is C 210 pi cm^3. Hope this helps
