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3 years ago

Select the processes that help to create a program.

Computers and Technology

1 answer:

notsponge [240]3 years ago

4 0

Answer:

See the explanation

Explanation:

I dont quite understand the question, but I assume we are asked to pick/ check the related action that could help create a program. So I would pick following actions:

O begin with an idea

O translate the pseudocode into Java programming code

O compile the Java code control unit

O execute the program

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3 years ago

Input 10 integers and display the following:

LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables

int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

int largest=INT_MIN;

int smallest=INT_MAX;

int n;

cout<<"Enter 10 Integers:";

// read 10 Integers

for(int a=0;a<10;a++)

{

cin>>n;

// find largest

if(n>largest)

largest=n;

// find smallest

if(n<smallest)

smallest=n;

// if input is even

if(n%2==0)

{

// sum of even

sum_even+=n;

// even count

eve_count++;

}

else

{

// sum of odd

sum_odd+=n;

// odd count

odd_count++;

}

// print sum of even

cout<<"Sum of all even numbers is: "<<sum_even<<endl;

// print sum of odd

cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

// print largest

cout<<"largest Integer is: "<<largest<<endl;

// print smallest

cout<<"smallest Integer is: "<<smallest<<endl;

// print even count

cout<<"count of even number is: "<<eve_count<<endl;

// print odd cout

cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4 2 10 11 12 44 5 20

Sum of all even numbers is: 92

Sum of all odd numbers is: 20

largest Integer is: 44

smallest Integer is: 1

count of even number is: 6

count of odd number is: 4

3 0

4 years ago