Answer:
x = 1
Step-by-step explanation:
Given:
We are asked to solve for x when the function is equal to zero.
<u>We should have</u>: 0 = -4x + 4
<u>Solve</u>
1. Subtract 4 from both sides
0 - 4 = -4x + 4 - 4
-4 = -4x
2. Divide both sides by -4
-4 ÷ -4 = -4x ÷ 4
1 = x
Michael will have 4 cards left because 265/9=29.4444444... then i do 29 (from the 29.4444) times 9 which gives me 261 and i did 265-261.
Let's assume two variables x and y which represent the local and international calls respectively.
x + y = 852 = total number of minutes which were consumed by the company (equation 1)
0.06*x+ 0.15 y =69.84 = total price which was charged for the phone calls (Equation 2)
from equation 1:-
x=852 -y (sub in equation 2)
0.06 (852 - y) + 0.15 y =69.84
51.12 -0.06 y +0.15 y =69.84 (subtracting both sides by 51.12)
0.09 y =18.74
y= 208 minutes = international minutes (sub in 1)
208+x=852 (By subtracting both sides by 208)
x = 852-208 = 644 minutes = local minutes
Answer: Reflection about x-axis
Step-by-step explanation:
Given
Initially, vertices are 
After reflection they become 
It is clear that the x coordinate remains unchanged and the y coordinate changes its sign. It occurs when reflection is done about the x-axis.
For example, when (a,b) is reflected about the x-axis, it becomes (a,-b).
So, here reflection is being done about the x-axis.
If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.
With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).
The molar mass of the element copper is determined by looking at its average atomic mass, which is 63.55 AMU on the periodic table. Since it is also our molar mass, we will now put it in a different unit: grams over moles (63.55 gmol). That is copper's molar mass.
If the solution is blue-green, there is still copper in the solution and not all of it has precipitated. Because you will have less bulk, anticipate it to be too low.
To know more about copper, refer to this link:
brainly.com/question/1543891
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