Question:
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.
What is the solution set of this problem?
Answer:

Step-by-step explanation:
Given
<em>Represent the number with x</em>
So:

Required
Determine the solution set

Open Both Brackets


Collect Like Terms


Multiply both sides by -1

Hence, the solution set is 
The answer to this is x < -10/7
Answer:
Option A
Step-by-step explanation:
22+(-32) is the same thing as 22-32.

<h3>Let's see if the given options are equal:</h3>
Option A:

Option A's expression has the same value as the expression given.
Option B:
22+(22)+(-10)

Option B's expression does not have the same value as the expression given.
Option C:

Option C's expression does not have the same value as the expression given.
Option D:

Option D's expression does not have the same value as the expression given.
<h3>The correct answer should be A: 22+(-22)+(-10).</h3>
Answer:
z=(sqrt(10)-1)/2 or z= -(sqrt(10)-1)//2
Step-by-step explanation:
To complete the square, the last term has to be 1. So adding 10 to both sides, we get:
4z^2+4z+1 = 10
Since 4z^2+4z+1=(2z+1)^2,
(2z+1)^2 = 10.
Taking the square root of both sides, we get
2z+1=sqrt(10) or 2z+1=-sqrt(10)
So z=(sqrt(10)-1)/2 or z= -(sqrt(10)-1)//2
Answer: -7
Step-by-step explanation:
-30 = 5(x + 1)
-30 = 5x + 5. ( After distrbuting the 5)
-5. -5
-30 - 5. = 5x
-35 = 5x
x = -7