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Evgesh-ka [11]
3 years ago
15

2 triangles are connected a common side. The length of one side is 2 x + 3. Its corresponding side on the second triangle is 9.

The length of another side is y minus 4. Its corresponding side on the second triangle is 7. Which of the following pairs of values for x and y would justify the claim that the two triangles are congruent? x = 3, y = 11 x = 5, y = 5 x = 7, y = 9 x = 9, y = 7
Mathematics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

x = 3, y = 11

Step-by-step explanation:

SSS for congruent

2x+3 = 9

x = 3

y-4 = 7

y = 11

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3 years ago
Through: (1, 2), parallel to y=-3x - 3​
Westkost [7]

The equation of the line that parallel to y = -3 x - 3 and passes

through the point (1 , 2) is y = -3 x + 5

Step-by-step explanation:

The slope-intercept form of an equation of a line is y = m x + c, where

m is the slope of the line and c is the y-intercept

→ Parallel lines have same slopes

→ Parallel lines have different y-intercepts

∵ The equation of a line is y = -3 x - 3

∵ The slope-intercept form of the equation of a line is y = m x + c

∴ m = -3

Let us write the equation of a line that parallel to the line y = -3 x - 3

∵ Parallel lines have same slopes

∵ The slope of the line above = -3

∴ The slope of the line = -3

∴ The equation of the line is y = -3 x + c

To find c substitute x and y in the equation by the coordinates of a

point lies on the line

∵ The line passes through the point (1 , 2)

- substitute x by 1 and y by 2 in the equation

∴ 2 = -3(1) + c

∴ 2 = -3 + c

- Add 3 to both sides

∴ 5 = c

- substitute the value of c in the equation

∴ The equation of the line is y = -3 x + 5

The equation of the line that parallel to y = -3 x - 3 and passes

through the point (1 , 2) is y = -3 x + 5

Learn more:

You can learn more about parallel lines in brainly.com/question/10483199

#Learnwithbrainly

6 0
3 years ago
You can represent an odd integer with the expression 2n+1, where n is any integer. write and solve an equation to find three con
Igoryamba
<span>I :  2n + 1 
II : 2n + 3
III : 2n +5
(2n + 1) + (2n + 3) +(2n+5)=63
6n+9=63
n=9
I : 2n+1=9*2+1=19
II : 2n+3=9*2+3=21
III : 2n+5=9*2+5=23

19+21+23=63

</span>
5 0
3 years ago
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