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Alex73 [517]
3 years ago
6

Help me out ? :) would me a lot, thanks

Mathematics
1 answer:
Goryan [66]3 years ago
7 0

\frac{5}{2}  =  \frac{s}{8 }  \\ 5 \times 8 = 2s \\  40 = 2s \\ s =  \frac{40}{2}  \\ s = 20

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The sampling distribution of x has a mean μₓ = <u> μ </u> and standard deviation σₓ =​ <u> σ/√n </u>.

In the question, we are given that a random sample of size n is drawn from a large population with mean μ and standard deviation σ.

We are asked to find the mean and the standard deviation for the sampling distribution of the variable x for this sample.

The sample mean is regularly distributed, with a mean μₓ = μ and standard deviation σₓ = σ/√n, where n is the sample size, for samples of any size taken from populations that have a normal distribution.

Thus, the sampling distribution of x has a mean μₓ= <u> μ </u> and standard deviation σₓ=​ <u> σ/√n </u>.

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Suppose a simple random sample of size n is drawn from a large population with mean μ and standard deviation σ.

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