Given functin is :
We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.
Domain: (-∞,∞)
Range is the set of y-values obtained by plugging values from domain so the range will also same.
Range: (-∞,∞)
If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.
It crosses x and y-axes both at the origin
Hence x-intercept=0 and y-intercept=0
Graph is not symmetric about y-axis hence it can't be EVEN
Graph is not symmetric about origin so it is ODD.
There is no breaking point in the graph so that means it is a Continuous function.
There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.
END behaviour means how y-changes when x approaches infinity.
From graph we can see that when x-approaches -∞ then y also approaches ∞.
when x-approaches +∞ then y also approaches +∞.
Answer:
8 x^6
Step-by-step explanation:
4x^3× 2x^3
Multiply the numbers
4*2 = 8
Then the variables
x^3 * x^3 = x^(3+3) = x^6
8 x^6
Answer:
See explanation below
Step-by-step explanation:
<u>First we will solve the radical equation</u> (which I guess was problem 1),
Let's start by simplifying it:
Now we will solve the equation by squaring both sides of the equation:
So the calculation for x was that x = -10
However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:
This happens because <u>when we first squared both sides of the equation in the first part of the problem we missed one value for x </u>(remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.
When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.
Answer:a is truwe
Step-by-step explanation:
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