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steposvetlana [31]
3 years ago
6

If there are 2 rabbits and they triple every month how many rabbits are there in three months?

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0
There are 56 rabbits
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Simplify (sec θ – tan θ)2
rusak2 [61]

Answer:

2 sec (θ )  −  2 tan ( θ )

Step-by-step explanation:

4 0
3 years ago
What is the solution to the following system of equations? x+y=5
marta [7]

Answer:

(3,2)

Step-by-step explanation:

Let's solve this via elimination method:

\begin{cases} x+y=5\\x-y=1\end{cases}

By subtracting equation 2 from equation one we obtain:

\begin{cases} x+y=5\\-(x-y=1)\end{cases}\\\\0x+2y=4\\\\y=2

Next we can use any equation either 1 or 2 to determine what x is, I'll use equation 1.  Let y=2 and so:

x+y=5\\\\x+2=5\\x=5-2\\\\x=3

Therefore the solution for the system of equations is:

x=3 and y = 2 as an ordered pair we have (3,2)

7 0
3 years ago
The longest side of an isosceles right triangle measures 16m. What is the perimeter ofthe triangle?
Andreyy89

Answer:

In right triangle hypotenus(side facing angle 90)is the longest

Step-by-step explanation:

lets say hyp=side1 +side2 were(side1=side2 in isocseles..) and Let x bet the length of side 1

So by applying phythegoras theorem :

hyp^2=x^2+x^2

16^2 =2x^2

2x^2=256

x^2=128

\sqrt{x { }^{2} }  =  \sqrt{128}

x=

8 \sqrt{2}

Parameter=16+8

8 \sqrt{2 }  + 8 \sqrt{2 }  + 16

16 \sqrt{2}  + 16

7 0
2 years ago
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

4 0
3 years ago
Use the equation: C=0.5n to determine the cost for 14 hamburgers in dollars
Goshia [24]
C=$7.00

C stands for the cost, and n would be the amount of hamburgers. Since we are looking to determine the costs of 14 hamburgers we would have to then multiply 0.5 and 14.

14 x 0.5 =7

So your answer is 7 dollars
7 0
3 years ago
Read 2 more answers
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