The average value of f(x) over [2, 6] is given by the definite integral,
![\displaystyle f_{\rm ave[2,6]} = \frac1{6-2} \int_2^6 3\ln(2+x^3)\cos(x) \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f_%7B%5Crm%20ave%5B2%2C6%5D%7D%20%3D%20%5Cfrac1%7B6-2%7D%20%5Cint_2%5E6%203%5Cln%282%2Bx%5E3%29%5Ccos%28x%29%20%5C%2C%20dx)
and is approximately -1.67284.
Answer:
4w+3
Step-by-step explanation:
2/3(7w+4)-1/3(2w-1)
14/3w+8/3-2/3w+1/3
14/3w-2/3w+8/3+1/3
12/3w+9/3
4w+3
Angle A is 2x + 3
Angle B is 4x + 2
Angle C is 2x - 1
The three angles add up to 180
So:
2x + 3 + 4x + 2 + 2x - 1 = 180
Combine terms
8x + 4 = 180
Subtract 4
8x = 176
x = 22
Now we solve for the angles:
Angle A is 2(22) + 3 = 44 + 3 = 47
Angle B is 4(22) + 2 = 88 + 2 = 90
Angle C is 2(22) - 1 = 44 - 1 = 43
Quick check: 47 + 90 + 43 = 180