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ratelena [41]
2 years ago
11

Its upside down but what are the answers to all of the equations?

Mathematics
2 answers:
Aneli [31]2 years ago
8 0
98 .3.1456834hfhfhfhfufufuf
elena-14-01-66 [18.8K]2 years ago
3 0

Answer: here I just fliped it

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Given: f(x) = x 2, g(x) = x + 6, h(x) = 7<br><br> Find h{g[f(x)] }.<br><br> a. 7<br> b. 20<br> c. 55
GarryVolchara [31]

Given f(x) = x^2 + 1 and g(x) = x-2

a. Find (f-g)(-2)

[f-g](x) = f(x) - g(x) = x^2-x+3

[f-g](-2) = (-2)^2-(-2)+3 = 9

----------------------------

b. Find f[g(5)]

f[g(5)] = f[5-2] = f[3] = 9+1 = 10

===================

problem a.

-----

(f-g)(x) = f(x) - g(x)

-----

(f-g)(-2) = f(-2) - g(-2)

-----

f(x) = x^2 + 1

f(-2) = (-2)^2 + 1

f(-2) = 4+1

f(-2) = 5

-----

g(x) = x-2

g(-2) = -2-2

g(-2) = -4

-----

f-g(-2) = f(-2) - g(-2) = 5 - (-4) = 5 + 4 = 9

-----

answer for a is:

f-g(-2) = 9

-----

problem b.

-----

g(x) = x-2

g(5) = 5-2

g(5) = 3

-----

f(x) = x^2 + 1

f(g(5)) = (g(5))^2 + 1

since g(5) = 3, equation becomes:

f(g(5)) = 3^2 + 1

f(g(5)) = 9 + 1 = 10

-----

answer for b is:

f(g(5)) = 10

-----

in general, you substitute whatever value is replacing x in the equation to get your answers.

looking at problem b in this way, we would get a general solution as follows:

f(x) = x^2 + 1

g(x) = x-2

substitute g(x) for x:

f(g(x)) = (g(x))^2 + 1

substitute the equation for g(x) on the right hand side.

f(g(x)) = (x-2)^2 + 1

remove parentheses:

f(g(x)) = x^2 - 4*x + 4 + 1

simplify:

f(g(x)) = x^2 - 4*x + 5

-----

substituting 5 for x:

f(g(5)) = (5^2 - 4*5 + 5

simplifying:

f(g(5)) = 25 - 20 + 5

f(g(5)) = 10

-----

answer is the same as above where we first solved for g(5) which became 3, and then substituted that value in f(g(x)) which made it f(3)).

Hope this helps!

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