<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144
Solution:
Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.
for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!
for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d
they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
Amma solve it first then ill tell you what i got as the answer:)
Out of a single week it's 2/7. Out of a month it'd be 8/30 with only 30 days in a month. I hope this helps.
The maximized value of the function is (c) 119/2
<h3>Maximization problem</h3>
Maximization problems are used to determine the optimal solution of a linear programming model
<h3>Objective function</h3>
The objective function is given as:
<h3>Constraints</h3>
The constraints are given as:
<h3>Graph</h3>
See attachment for the graph of the constraints
From the graph, the optimal solution is: (2.83, 2.83)
So, the maximized value is:
Approximate
Rewrite as a fraction
Hence, the maximized value of the function is (c) 119/2
Read more about maximization problem at:
brainly.com/question/16826001
Answer:
x=1, y=-1. (1, -1).
Step-by-step explanation:
2x+3y=-1
3x+5y=-2
-----------------
3(2x+3y)=3(-1)
-2(3x+5y)=-2(-2)
-------------------------
6x+9y=-3
-6x-10y=4
--------------
-y=1
y=-1
2x+3(-1)=-1
2x-3=-1
2x=-1+3
2x=2
x=2/2
x=1
