Answer:
If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. When you solve an equation, you find the value of the variable that makes the equation true. In order to solve the equation, you isolate the variable.
Answer:
x-intercept: <u>(1,0)</u>
y-intercept: <u>(0,1)</u>
Step-by-step explanation:
Given: Find the x and y intercepts of 2x + 2y = 2
<h2><u>X-intercept</u></h2>
To solve for a x - intercept we have to substitue 0 in for y and solve for 
Lets do it:
2x + 2(0) = 2
2x + 0 = 2
2x = 2
x = 1
Therefore, this means that when y = 0, x = 1 or (1,0)
<h2><u>Y-intercept</u></h2>
To solve for a y - intercept we have to substitue 0 in for x and solve for 
Lets do it:
2(0) + 2y = 2
0 + 2y = 2
2y = 2
y = 1
Therefore, this means that when x = 0, y = 1 or (0,1)
Answer:
This is mode defined
Step-by-step explanation:
Answer:
7.5s
1.6666 repeating or 1.67 m/s²
Step-by-step explanation:
the equation you have to use is Vfinal=Vstart+acceleration•time
(I'm gonna simplify to Vf=Vs+at)
so you gotta rework it for the two equations
for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at
then divide acceleration on both sides to get t=(Vf–Vs)/a
for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)
so you the plug in
(I don't put the units in to the problem unless needed)
1. t=(Vf–Vs)/a to t=(0–30)/-4.0
t= -30/-4.0
t=7.5 seconds
2. a=(Vf–Vs)/t to a=(10–0)/6.0
a= 10/6.0
a= 1.67m/s²
(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)
