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Ksivusya [100]
3 years ago
15

A box that has a width of 5 inches and a length of 12 inches is used to ship a part. The part lies along the diagonal of the bot

tom of the box. What is the longest possible length of the part?
Mathematics
1 answer:
RUDIKE [14]3 years ago
8 0

Answer:

13 inches

Step-by-step explanation:

Draw a square and draw a diagonal line through it. It creates a right triangle. So we can then use the Pythagoras theorem to find the length of the object at it's max. so we do a^2+b^2=c^2. So we do (12*12) + (5*5) = 169 and the square root of 169 is 13.

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17+6=23                that is the answer

3 0
3 years ago
The smallest multiple of 50​
trasher [3.6K]

Answer:

1

Step-by-step explanation:

One is the smallest multiple of 50. We can find this by finding all the multiples of 50. The multiples of 50 are: 1, 2, 5, 10, 25, and 50.

We can see that one is the smallest multiple because it is less than 2, 5, 10, 25 and 50. So, that means the answer to the question is 1.

Hope this helps.

6 0
2 years ago
Read 2 more answers
2, 7, 26, 101, 400, next number in pattern?
uranmaximum [27]

Answer:

1480

Step-by-step explanation:

26 / 7 is 3.7. 2 x 3.7 = 7.  400 x 3.7 = 1480

7 0
3 years ago
Can the sides of a triangle have lengths 2, 7, and 8?
Natalka [10]

Answer:

Yes

Step-by-step explanation:

As long as any two numbers added are greater than the number not chosen they can make a triangle

2+7= 9     9 is greater than 8

8+2= 10    10 is greater than 7

7+8= 15 .  15 is greater than 2

3 0
3 years ago
If you roll two number cubes ,what is the probability of their sum being 9 or higher?
bija089 [108]

Answer:

5/18

Step-by-step explanation:

When two cubes are rolled there are 36 possibilities

Each dice has 6 equally like outcomes so possibilities are

(1,1)  (1,2)          (1,3)          (1,4)         (1,5)         (1,6)

(2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

(3,1)  (3,2)  (3,3)  (3,4)  (3,5)  (3,6)

(4,1)  (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

(5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

(6,1)  (6,2)  (6,3)  (6,4)  (6,5)  (6,6)

Now we look at the pair that has sum equal to 9

(3,6) (4,5) (5,4) (6,3) that has sum of 9

Probability of sum is 9 = \frac{4}{36}

we look at the pairs that has sum greater than 9

(4,6) (5,5)(5,6) (6,4)(6,5)(6,6)

Probability of sum greater than 9 = \frac{6}{36}

Probability of sum 9 or higher = P(sum 9) + P(greater than 9)

= \frac{4}{36}+\frac{6}{36}= \frac{10}{36}=\frac{5}{18}



4 0
3 years ago
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