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Ksivusya [100]
3 years ago
15

A box that has a width of 5 inches and a length of 12 inches is used to ship a part. The part lies along the diagonal of the bot

tom of the box. What is the longest possible length of the part?
Mathematics
1 answer:
RUDIKE [14]3 years ago
8 0

Answer:

13 inches

Step-by-step explanation:

Draw a square and draw a diagonal line through it. It creates a right triangle. So we can then use the Pythagoras theorem to find the length of the object at it's max. so we do a^2+b^2=c^2. So we do (12*12) + (5*5) = 169 and the square root of 169 is 13.

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Use double number lines to find the missing number. Write a percent proportion and solve each problem.
GaryK [48]
Your answer is: 63 is 90% of 70.

The work (if needed) is shown above :)

6 0
2 years ago
Translate this sentence into a multi-step equation Six more than the quotient of a number and 8 is equal to 2.
Korvikt [17]

Answer:

6+n/8=2

Step-by-step explanation:

* More Than = (+) or in some cases (>)

* Quotient of a (#) = Any letter that represents a number, so in this case "n", because we do not know that number yet. We divide this with "8" because it says "and 8".

* Equal = <---

5 0
2 years ago
Bruce owns a business that produces widgets. He must bring in more in revenue than he pays out in costs in order to turn a profi
Aliun [14]
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8 0
3 years ago
100 POINTS PLEASE HURRY
Harlamova29_29 [7]

Answer:

5.80 to the power of 3. I would say this is the answer if you just look closely at the number line and you will see the answer

6 0
2 years ago
Read 2 more answers
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
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