Answer:
The magnitude of the sum of A and B is 27.51 N.
Explanation:
We can separate the x- and y-components of the vectors, then sum these components separately. Afterwards, we can calculate the magnitude of the sum.
On the other hand, for the vector B:
The sum of the components in the x-direction is equal to 22.85 N.
The sum of the components in the y-direction is equal to 15.32 N.
Finally, the magnitude of the sum vector C is
Distance traveled by the ball is given by
here we know that
speed = 20 m/s
times = 0.25 s
now we have
so ball will travel 5 m distance in the given interval of time
Answer:
The speed of the car at the end of the 2nd second = 8.0 m/s
Explanation:
The equations of motion will be used to solve this problem.
A car starts from rest,
u = initial velocity of the car = 0 m/s
Accelerates at a constant rate in a straight line,
a = constant acceleration of the car = ?
In the first second the car moves a distance of 2.0 meters,
t = 1.0 s
x = distance covered = 2.0 m
x = ut + (1/2)at²
2 = 0 + (1/2)(a)(1²)
a = 4.0 m/s²
How fast will the car be moving at the end of the second second
Now,
a = 4.0 m/s²
u = initial velocity of the car at 0 seconds = 0 m/s
v = final velocity of the car at the end of the 2nd second = ?
t = 2.0 s
v = u + at
v = 0 + (4×2)
v = 8.0 m/s
Answer:
The resistance will be 2×R
Explanation:
We note that the resistivity of a cylindrical wire is given by the following relation;
Where:
ρ = Resistivity of the wire
R = The wire resistance
A = Cross sectional area of the wire = π·D²/4
L = Length of the wire
Rearranging, we have;
If the length and the diameter are both cut in half, we have;
L₂ = L/2
A₂ =π·D₂²/4 =
Therefore, the new resistance, R₂ can be expressed as follows;
Hence, the new resistance R₂ = 2×R, that is the resistance will be doubled.