Answer:
use a=v-u/t formula it will be correct
A-11 polar easterlies
b-8 winds blowing between the equator and 30° N and south
c-10
d-9
Answer:
Explanation:
Remark
At the time it takes to drop 20 m is the same time it takes to travel 60 m horizontally.
Givens
h = 20 m
hd = 60 m
g = 9.81
vi = 0
Formula
d = vi*t + 1/2 a * t^2 We are solving for t
Solution
When the battery fails, the vertical initial velocity is 0. So we have to find the time it would take to drop 20 meters
d = 0*t + 1/2 * 9.81 a* t^2
20 = 4.91 * t^2 Divide by 4.91
20/4.91 = 4.91 t^2 / 4.91
4.073 = t^2 Take the square root of both sides.
t = 2.02 seconds
Horizontal
d = 60 m
t = 2.02 seconds
v = ?
Note: there is no horizontal deceleration or acceleration
v = d/t
v = 60/2.02
Answer: v = 29.73 m/s
Answer:16.3
Explanation:the
Explanation is in words
on a pic and i showed extra proof
Answer:
a)
Weight in Air = 0.3N
Weight in Water = 0.25N
Weight in Liquid = 0.24N.
Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)
= 0.3 – 0.25
= 0.5N.
b) R.D of Body = Density of Body/Density of Standard Fluid(Water).
There's a Derived Formula for RD.
I'm gonna Apply it here.
Ask me for the derivation in the Comment section if you need it.
RD = α/ρ = (Weight in Air) / (Upthrust Force)
Where
α = density of the Body(or reference substance)
ρ = density of standard fluid (water)
= 0.3/0.05 = 6.
c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)
Or we just go by that formula
RD of Liquid = Weight in Air/Upthrust(In Liquid)
We'll be using the Upthrust in that Liquid now.
= 0.3 – 0.24 = 0.06
RD = 0.3/0.06 = 5.