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Alik [6]
3 years ago
14

Charge is uniformly distributed throughout a spherical insulating volume of radius R=4.00 cm . The charge per unit volume is −6.

5 μCm3 Find the electric field at the center of the sphere. Enter a positive number if the field points radially out, negative if the field points radially in, or zero if there is no field.
Physics
1 answer:
aleksley [76]3 years ago
8 0

Answer

-8.67× 10^6 N/C

Explanation:

The Electric Field is defined as force per unit charge.

E = Q/ 4π£r2

Qv= −6.5 μCm3

Qv = Q/ V= Q/ 4/3 πr3

Hence Q = 4/3 πr3 × Qv

Hence E = 4/3 πr3 × Qv / 4π£r2= Qvr/3£

−6.5 μ × 4/ 3×8.854 ×10^-12

-6.5 × 4 × 10^6/3 = -8.67× 10^6 N/C

Note: £ = 8.854×10^-12m/F

is the permittivity of free space

Qv is the charge per unit volume

V is volume and volume

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Answer:

It would change the amount of heat produced in the transmission line to four times the previous value.

Explanation:

Given;

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The power lost in the transmission line due to heat is given by;

P = \frac{V^2}{R}

Power lost in the first wire;

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Power lost in the second wire

P_2 = \frac{V_2^2}{R}\\\\ R = \frac{V_2^2}{P_2}

Keeping the resistance constant, we will have the following equation;

\frac{V_2^2}{P_2} = \frac{V_1^2}{P_1} \\\\P_2 = \frac{V_2^2P_1}{V_1^2}\\\\

P_2 = \frac{(1,000,000)^2P_1}{(500,000)^2}\\\\P_2 =4P_1

Therefore, it would change the amount of heat produced in the transmission line to four times the previous value.

8 0
3 years ago
As 390-g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment.
stiks02 [169]
Q = m.s.Δt
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Here, Q = 30,000 J
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s = 3.9 J/g C

Substitute their values, 
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Hope this helps!

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3 years ago
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Answer:

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Explanation:

The weight in grams is equal to the pounds multiplied by 453.59237.

So... you would multiply 7.93 by 453.59237.

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Explanation:

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