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mina [271]
3 years ago
7

A set of four stars form the shape of a rectangle in space. The length of the rectangle is approximately 6,750,000,000 miles, wh

ile the width of the rectangle is approximately 36,100,000 miles. What is the approximate area of the rectangle?
Mathematics
1 answer:
maksim [4K]3 years ago
3 0

Answer:

2.43675e+17

Step-by-step explanation:

sorry used calculator.

but still hope that this is correct.

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A. Perfect square Trinomial

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3 years ago
How do you solve this triangle by using the law of sine where
mars1129 [50]
Actually, when you know 2 sides and an included angle, you use the Law of Cosines. (and we don't know if theta is an included angle).
Solving for side c
c^2 = a^2 + b^2 -2ab * cos(C)
c^2 = 36 + 16 - 2*6*4 * cos(60)
c^2 = 52 -48*.5
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Using the Law of Sines
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5.2915 / sin(60) = 4 / sin (B)
sin(B) = sin(60) * 4 / 5.2915
sin(B) = 0.86603 * 4 / 5.2915
<span><span>sin(B) = 3.46412 </span> / 5.2915
</span> <span><span><span>sin(B) = 0.6546571451 </span> </span> </span> 
Angle B = 40.894 Degrees

sin (A) / side a = sin (B) / side b
sin (A) = 6 * sin (40.894) / 4
sin (A) = 6 * 0.65466 / 4
sin (A) = .98199
angle A = 79.109 Degrees

angle C = 60 Degrees


7 0
4 years ago
Plz help these r the last of my points
IRINA_888 [86]
w=61, the equation is w=(456-a-b-c)/2,  so the work would look like 456-132-94-108=122/2=61
3 0
3 years ago
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