What could using cobalt glass be helpful to identify?

Chemistry

1 answer:

satela [25.4K]2 years ago

5 0

Answer:

Using cobalt glass could be helpful to identify elements that weakly emit blue and/or violet.

Explanation:

You might be interested in

There are ________ mol of bromide ions in 0.700 L of a 0.400 M solution of AlBr

denis23 [38]

Answer:

The number of moles of AlBr3 = Molarity × Volume

= 0.400 × 0.700

= 0.28 moles

1 mole of AlBr3 gives 3 moles of Br- ions

That is

AlBr3 = Al3+ + 3Br-

Therefore, 0.045 moles of AlBr3 will yield 3 × 0.28 = 0.84 moles

Thus; they are 0.84 moles of bromide ions

5 0

2 years ago

Plzz some one tell me tha objection 5 6 points to kekule formula

kakasveta [241]

A structural formula for an organic compound that depicts each valence bond as a short line especially : the hexagonal ring formula for benzene

6 0

3 years ago

What is the answer pls help me

scZoUnD [109]

It’s definitely magnesium but it may not be

3 0

3 years ago

If each NADHNADH generates 3 ATPATP molecules and each FADH2FADH2 generates 2 ATPATP molecules, calculate the number of ATPATP m

Nadusha1986 [10]

Answer:

$128~ATP$

Explanation:

The metabolic pathway by which energy can be obtained from a fatty acid is called "beta-oxidation". In this route, acetyl-Coa is produced by removing 2 carbons from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the number of rounds that will take place for an 18-carbon fatty acid using the following equation:

$Number~of~Rounds=\frac{n}{2}-1$

Where "n" is the number of carbons, in this case "18", so:

$Number~of~Rounds=\frac{18}{2}-1~=~8$

We also have to calculate the amount of Acetyl-Coa produced:

$Number~of~Acetyl-Coa=\frac{18}{2}~=~9$

Now, we have to keep in mind that in each round in the beta-oxidation we will have the production of 1 $FADH_2$ and 1 $NADH$ . So, if we have 8 rounds we will have 8 $FADH_2$ and 8 $NADH$ .