What could using cobalt glass be helpful to identify?

Chemistry

1 answer:

satela [25.4K]2 years ago

5 0

Answer:

Using cobalt glass could be helpful to identify elements that weakly emit blue and/or violet.

Explanation:

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Calcium reacts with bromine to form calcium bromide. 2.1 Which atom will lose electrons? 2.2 How many electrons will it lose? 2.

Juli2301 [7.4K]

<u>Answer:</u>

<u>For 2.1:</u> Calcium atom will loose electrons.

<u>For 2.2:</u> It will loose 2 electrons.

<u>For 2.3:</u> Bromine atom will gain electrons.

<u>For 2.4:</u> It will gain 1 electron.

<u>For 2.5:</u> The ions formed are $Ca^{2+}\text{ and }Br^-$

<u>For 2.6:</u> The chemical formula is $CaBr_2$

<u>Explanation:</u>

Calcium bromide is formed by the combination of calcium and bromine atoms. This compound is ionic compound because electrons get transferred from one atom to another atom.

Calcium is the 20th element of the periodic table. It is a metal and it looses its electrons. The electronic configuration for this element is $1s^22s^22p^63s^23p^64s^2$

This element will loose 2 electrons and forms $Ca^{2+}$ ion.

Bromine is the 35th element of the periodic table. It is a non-metal and it gains electrons. The electronic configuration for this element is $[Ar]4s^23d^{10}4p^5$