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Natasha_Volkova [10]
3 years ago
8

How many atoms are present in a sample of Potassium (K) weighing 33.49g?

Chemistry
1 answer:
madam [21]3 years ago
3 0

Answer:

5.158 × 10²³ atoms K

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

33.49 g K

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of K - 39.10 g/mol

<u>Step 3: Convert</u>

<u />33.49 \ g \ K(\frac{1 \ mol \ K}{39.10 \ g \ K} )(\frac{6.022 \cdot 10^{23} \ atoms \ K}{1 \ mol \ K} ) = 5.15797 × 10²³ atoms K

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig figs and round.</em>

5.15797 × 10²³ atoms K ≈ 5.158 × 10²³ atoms K

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